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3 years ago

Which expression represents the value of the series below? 3 + 7 + 11 + 15 + ... + 1,671

Mathematics

2 answers:

givi [52]3 years ago

8 0

I am pretty sure it is 4 i think

Paraphin [41]3 years ago

7 0

I think that the answer is x+4

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The relationship between the radius, r, of a sphere and its surface area, A, is r = ( A /4 π ) 1/2. What is the radius of a sphe

blagie [28]

Answer:

8 units

Step-by-step explanation:

Given the relationship between the radius, r, of a sphere and its surface area, A expressed as;

r = 1/2( A /4 π )

We are to find the radius r when Area A is 64π

Substitute A = 64π into the expression and get r as shown;

Recall that: r = 1/2( A /4 π )

r = 1/2( 64 π/4 π )

r = 1/2(16)

r = 16/2

r = 8units

Hence the radius of the sphere will be 8 units

8 0

3 years ago

Julia has 4 gallons 2 quarts of water. Ally needs the same amount of water but only has 12 quarts. How much more water does ally

skad [1K]

Answer: Ally would need 6 more quarts of water.
Explanation: Since 4 quarts equal 1 gallon, 4*4 = 16 + 2 = 18, Julia would have 18 quarts. Subtract 12 from 18 to get 6 quarts.

5 0

4 years ago

Which shows a correct order to solve this story problem?

borishaifa [10]

A-Step 1 Multiply 18.9 × 3.
Step 3. Add 18.9 from the product. is the right answer. Why?
This week the distance travelled was 3x 18.9 father than last week, it means

18.9x3 + 18.9=75.6

7 0

4 years ago

Read 2 more answers

Help me please and thank u

marin [14]

$\large \mathfrak{Solution : }$

As we know :

Dividend = Divisor × Quotient ( taking remainder as 0 )

So, Quotient = Dividend ÷ Divisor

by using the above relation we can say :

q = t ÷ 23

therefore, correct option is C. t ÷ 23

6 0

3 years ago

At time t hours after taking the cough suppressant hydrocodone bitartrate, the amount, A, in mg, remaining in the body is given

Nostrana [21]

Answer:

a. The initial amount was 10 mg.

b. The percentage of the drug leaving the body each hour is 0.18, this is 18% per hour.

c. The amount of drug that remains in the body 6 hours after dosing is 3.04 mg.

d. The time until only 1 mg of the drug remains in the body is 11.6 hours.

Step-by-step explanation:

You know that at time t hours after taking the cough suppressant hydrocodone bitartrate, the amount, A, in mg, remaining in the body is given by :

$A=10*(0.82)^{t}$

a. The initial quantity occurs when time t is the initial t, that is, t is equal to 0. Then:

$A=10*(0.82)^{t}=10*(0.82)^{0}=10*1\\$

A=10

The initial amount was 10 mg.

b. Considering that an exponential growth is determined by:

$A=A0*(1-r)^{t}$ , where A is the amount after a certain number of a certain time, Ao is the initial amount, r is the rate and t is the time, so the percentage of the drug that leaves the body each hour is :

1-r=0.82

Solving:

1-r -1= 0.82 -1

-r= -0.18

r= 0.18

The percentage of the drug leaving the body each hour is 0.18, this is 18% per hour.

c. The amount of drug that remains in the body 6 hours after dosing is when t = 6:

$A=10*(0.82)^{6}$

Solving:

A= 3.04 mg

The amount of drug that remains in the body 6 hours after dosing is 3.04 mg.

d. The time that passes until only 1 mg of the drug remains in the body is calculated taking into account that A = 1 mg:

$1=10*(0.82)^{t}$

Solving:

$0.1=(0.82)^{t}$

㏒ 0.1= t*㏒ 0.82

㏒ 0.1 ÷ ㏒ 0.82= t

11.6 hours= t

The time until only 1 mg of the drug remains in the body is 11.6 hours.

4 0

3 years ago