Let <em>f(x)</em> = <em>x</em>³ + <em>x</em> - 5. <em>f(x)</em> is a polynomial so it's continuous everywhere on its domain (all real numbers). Since
<em>f</em> (1) = 1³ + 1 - 5 = -3 < 0
and
<em>f</em> (2) = 2³ + 2 - 5 = 5 > 0
it follows by the intermediate value theorem that there at least one number <em>x</em> = <em>c</em> between 1 and 2 for which <em>f(c)</em> = 0.
12
13
78
97
65
90
70
these are numbers with 2 digits
Answer:
1/6
Step-by-step explanation:
No. Of faces contains 4=1
Total no. Of faces=6
Probablity = favourable no. of outcomes/Total no. of outcomes
PLEASE GIVE BRAINLIEST
Answer:
We can use slope intercept form to get the points needed. Y= -7+1/3x The points are (0,-7) and (3,-6)
Step-by-step explanation:
Subtract 2x from the left side and place it over to the right side with the 42. Now we have -6y= 42-2x. From here we divide by -6 and we get y= -7+1/3x. We know that are slope is 1/3 which the one is the rise and the 3 is the run. We also know that our y intercept is -7. We plot the points at (0,-7) and (3,-6)
