Initial velocity of the plane is Vo = 0.
acceleration a = 1.3 m/s2
total distance = 2.5 km = 2500m
time taken to reach 2.5 km with 1.3m/s^2 acceleration = t
S = Vo t + 0.5 a t^2
2500 = 0 + (0.5*1.3* t^2)
t^2 = 3846.15
t = 62 s
the maximum velocity plan can reach within 62 s is Vt
Vt = Vo + a t
Vt = 0 + (1.3*62)
Vt = 80.6 m/s
Since 80.6 m/s is greater than 75 m/s, plane can use this runway to takeoff with required speed.
Answer:
The discount% is 15%
Step-by-step explanation:
Given : The price of a sweater was slashed from Rs 960 to Rs 816 by a shopkeeper in the winter season.
To find : The rate of discount given by him?
Solution :
According to question,
The market price of the sweater is Rs.960
The selling price of the sweater is Rs.816
The discount on the sweater is given bY
Discount % is given by
Therefore, The discount% is 15%.
I think the answer is 17 because the pattern adds 4 then takes away 1 so 14-1=13 13+4=17
-6+3=-3 :-) hope that help
