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katrin2010 [14]

3 years ago

8

A rectangle with an area of 47 m² is dilated by a factor of 7. What is the area of the dilated rectangle?

1 answer:

MA_775_DIABLO [31]3 years ago

8 0

We already know that the area of the rectangle increased by a square of the factor 7. So the dilated area of it (which we will call "Ad"), is:

Ad= (47)(7^2)
Ad= 47x49
Ad= 2303 m^2

What is the area of the dilated rectangle? The area of the dilated rectangle is 2303 m^2.

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Based on the diagram shown, find θ to the nearest degree.

sattari [20]

Answer:

θ = 38°

Step-by-step explanation:

The lower right triangle is congruent to the upper left triangle, so we have θ and 20° being the two acute angles in the triangle. The law of sines tells you ...

sin(θ)/9 = sin(20°)/5

sin(θ) = (9/5)sin(20°)

θ = arcsin(9/5·sin(20°)) ≈ 38°

___

Another solution to the triangle is θ = 180° -38° = 142°. The diagram clearly shows θ as an acute angle, so we take this second solution to be extraneous.

8 0

3 years ago

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ankoles [38]

Answer:

The diameter is related because it helps find the circumference.

5 0

3 years ago

Which statement describes the behavior of the function f(x)=3x/4-x?

Oksana_A [137]

Answer:

The graph approaches –3 as x approaches infinity. Option a is correct.

Step-by-step explanation:

The given function is

$f(x)=\frac{3x}{4-x}$

We have to find value of function as x approaches infinity. Take limit both sides as x approaches to infinity.

$\lim_{x\rightarrow \infty}f(x)=\lim_{x\rightarrow \infty}\frac{3x}{4-x}$

Taking x common from the denominator.

$\lim_{x\rightarrow \infty}f(x)=\lim_{x\rightarrow \infty}\frac{3x}{x(\frac{4}{x}-1)}$

Cancel out common factor x.

$\lim_{x\rightarrow \infty}f(x)=\lim_{x\rightarrow \infty}\frac{3}{\frac{4}{x}-1}$

Apply limits.

$\lim_{x\rightarrow \infty}f(x)=\frac{3}{\frac{4}{\infty}-1}$

$\lim_{x\rightarrow \infty}f(x)=\frac{3}{0-1}$

$\lim_{x\rightarrow \infty}f(x)=-3$

Therefore the graph approaches –3 as x approaches infinity.

7 0

3 years ago

Read 2 more answers

Seis manzanas y 8 peras cuestan $26. ¿Cuanto cuesta cada pera y cada manzana sabiendo que cada manzana cuesta el triple de lo qu

Rom4ik [11]

Usando un sistema de ecuaciones, se encuentra que

Cada manzana cuesta $3.
Cada pera cuesta $1.

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Un sistema de ecuaciones soluciona esta pergunta.
El custo de una manzana es x.
El custo de una pera es y.

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<u>Seis manzanas y 8 peras cuestan $26</u>, o sea, $6x + 8y = 26$
<u>Cada manzana cuesta el triple de cada pera</u>, o sea, $x = 3y$

-----------------------

Primero, encontramos el cuesto de una pera, substituyendo la segunda en la primera ecuación.

$6x + 8y = 26$

$6(3y) + 8y = 26$

$18y + 8y = 26$

$26y = 26$

$y = \frac{26}{26}$

$y = 1$

Cada pera cuesta $1.

-----------------------

<u>Cada manzana cuesta el triple de cada pera</u>, o sea, $x = 3y = 3(1) = 3$ .

Cada manzana cuesta $3.

Se encuentra um problema similar en brainly.com/question/24646137

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2 years ago

Please help :) attached is a photo of the problem!

Mrrafil [7]

Answer:

Oh use M A T H W A Y

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3 years ago