All categories

3 years ago

Write an equation that passes through -2 and 5 and perpendicular to x=7? y=mx+b

Mathematics

1 answer:

GarryVolchara [31]3 years ago

4 0

Answer:

Step-by-step explanation:

I'm going to assume you mean passes through the point (-2,5) since -2 and 5 could mean a lot of different things

To find the perpendicular line's gradient, you would know that m1*m2 = -1

In this case m1 = 7, so m2 must be -1/7

Now we substitute the gradient into the equation

y = -1/7x + b

To find b, we substitute (-2,5) into the equation above

5 = -1/7*-2+b

5 = 2/7 + b

b = 33/7

Therefore the equation of the line is

y = -1/7x+33/7

You might be interested in

The distance between Earth to Neptune is approximately 4.3514 x 10^9

Scrat [10]

The answer would be D)Kilometers.

7 0

3 years ago

a pyramid whose altitude is 5ft weighs 800lbs. at what distance from its vertex must it be cut by a plane parallel to its base s

slavikrds [6]

A structure which has a square base and four triangular sides meeting at a point is called pyramid.

At distance of 3.97 feet from its vertex , pyramid is cut by plane so that the two solids of equal weight will be formed.

<u>It is assumed that weight of pyramid is proportional to its volume.</u>

So, $w = k V$ , where V is volume of original pyramid and v is volume of small pyramid and k is constant.

Let us consider that at h distance, pyramid is cut from its vertex. So a small pyramid is also formed.

Assume that base area of original pyramid is A and base of small pyramid is a.

Volume of original pyramid is, $V= \frac{1}{3} *A* 5$

So, weight of original pyramid, $W = k *(\frac{1}{3} *A* 5) = 800$

Volume of small pyramid is, $v = \frac{1}{3}* a* h$

So, weight of small pyramid, $w = k*(\frac{1}{3}* a* h)=400$

<u>Since, base and height of small pyramid and original pyramid are in proportion.</u>

So, $\frac{a}{A} = (\frac{h}{5}) ^{2}$

$a = (\frac{h}{5} )^{2}A$

Substituting value of a in equation $k*(\frac{1}{3}* a* h)=400$

So, $k*(\frac{1}{3}* \frac{h^{2} }{25}A * h)=400$

$(k*\frac{1}{3}* A*5)*\frac{1}{5} *\frac{h^{2} }{25} * h)=400$

Since, $(k *\frac{1}{3} *A* 5) = 800$ , substitute in above equation.

So, $800*\frac{h^{3} }{125}=400\\\\h^{3}=\frac{125}{2}\\\\h=\sqrt[\frac{1}{3} ]{62.5}\\\\h=3.97 feet$

Learn more:

brainly.com/question/17950304

6 0

2 years ago

Read 2 more answers

Anna has leaned a ladder against the side of her house. If the ladder forms a 72º angle with the ground and rests against the ho

LuckyWell [14K]

Answer:

(A) 2 meter

Step-by-step explanation:

It is given that the ladder forms a 72º angle with the ground and rests against the house at a spot that is 6 meters high.

Let the measure of bottom of the ladder from the wall be x, then using the trigonometry, we have

$\frac{CB}{AB}=tan72^{\circ}$

$\frac{6}{x}=tan72^{\circ}$

$\frac{6}{x}=3.077$

$x=\frac{6}{3.077}$

$x=1.94$

$x$ ≈ $2m$

Thus, option A is correct.

6 0

3 years ago

Read 2 more answers

X+ 0.0825×=216.50 A.) x=2.00 B.) x=20.0 C.) x=200 D.) x=2000

Luden [163]

X+0.0825x=216.5
1.0825x=216.5
x=216.5 / 1.0825
x=200

Answer: C.) x=200

8 0

3 years ago

Please tell me what this answer is

sdas [7]

Please like this I need pts

7 0

3 years ago