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photoshop1234 [79]
2 years ago
11

Write an equation that passes through -2 and 5 and perpendicular to x=7? y=mx+b

Mathematics
1 answer:
GarryVolchara [31]2 years ago
4 0

Answer:

Step-by-step explanation:

I'm going to assume you mean passes through the point (-2,5) since -2 and 5 could mean a lot of different things

To find the perpendicular line's gradient, you would know that m1*m2 = -1

In this case m1 = 7, so m2 must be -1/7

Now we substitute the gradient into the equation

y = -1/7x + b

To find b, we substitute (-2,5) into the equation above

5 = -1/7*-2+b

5 = 2/7 + b

b = 33/7

Therefore the equation of the line is

y = -1/7x+33/7

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3 years ago
Read 2 more answers
Given f(x)=x^4-7x^3+6x^2+8x+9
posledela
The workings to the answers are in the attachments below. Open them up in a new window to see them in full.

Lowest Point On The Graph:

(4.480878208, -61.32441280)

Highest Point On The Graph:

(1.155422854, 17.23818241)

2nd Lowest Point On The Graph:

(-0.3863010618, 7.23076164)

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3 years ago
What is the slope? 25 POINTS
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Step-by-step explanation:

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8 0
3 years ago
Step by step how to factor:<br> 2y^2+9y+9=0
weeeeeb [17]
Use ac method
for ax²+bx+c=0 when a≠1


multiply a and c, let's call the product r
what 2 numbesr multiply to get r and add to get b


2y²+9y+9=0
2*9=18
wat 2 numbers multiply to get 18 and add to get 9
3 and 6
split it up to that

2y²+3y+6y+9=0
group
(2y²+3y)+(6y+9)=0
factor
y(2y+3)+3(2y+3)=0
undistribute
(y+3)(2y+3)=0
set to zero

y+3=0
y=-3

2y+3=0
2y=-3
y=-3/2


y=-3 and -3/2
it's factored form is (x+3)(2x+3)
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