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3 years ago

I need to find the missing angle and arc measures. please answer Step by step

Mathematics

1 answer:

Daniel [21]3 years ago

5 0

9514 1404 393

Answer:

1: 40°; 2: 110°; 3: 70°; 4: 45°; 5: 65°

6: 70°; 7: 70°; 8: 65°; 9: 45°; 10: 17.5°

11: 15°; 12: 37.5°; 13: 70°; 14: 72.5°; 15: 20°

16: 87.5°; 17: 77.5°; 18: 35°; 19: 75°; 20: 20°

21: 50°; 22: 95°

Step-by-step explanation:

The angles are shown in the attached. The following relationships are used to find them.

an inscribed angle is half the measure of the arc it subtends
the sum of angles in a triangle is 180°
the angles where chords cross are half the sum of the intercepted arcs
the total of arcs in a semicircle is 180°
an exterior angle of a triangle is equal to the sum of the remote interior angles
acute angles in a right triangle are complementary

_____

All of the arcs around the circle are shown except EL and HN. EL is the difference between 180° and the other marked angles in semicircle SLH. It is 90°. HN has a vertical central angle with arc SE, so is the same measure, 40°.

Angle 1 is the central angle for arc HN, so has the same measure: 40°.

Angle 2 is half the sum of arcs SL and HW, so is (130+90)/2 = 110°.

Angle 3 is vertical to the second remote interior angle in triangle BDQ where angle 2 is an exterior angle. That is ∠3 = ∠2 -∠1 = 110° -40° = 70°.

Angle 4 is half arc NL, so is (40° +30° +20°)/2 =45°.

Angle 5 is the remaining interior angle of ∆BNW, so is 180° -70° -45° = 65°.

Angle 6 is half of arc HE, so is (30° +20° +90°)/2 = 70°.

Angle 7 is half of arc SN, so is 140°/2 = 70°.

— note that triangle HNQ is an isosceles triangle with central angle 40°, so the two base angles (∠6 and ∠7) are (180° -40°)/2 = 70°.

Angle 8 is half the measure of arc LS, so is (90° +40°)/2 = 65°.

Angle 9 is half the measure of arc HW, so is (40° +50°)/2 = 45°.

Angle 10 is half the measure of arc ST, so is 35°/2 = 17.5°.

Angle 11 is half the measure of arc OT, so is 30°/2 = 15°.

Angle 12 is half the measure of arc NO, so is (50° +25°)/2 = 37.5°.

Angle 13 is half the measure of arc HE, so is 140°/2 = 70°.

Angle 14 is half the measure of arc HT, so is (180° -35°)/2 = 72.5°.

Angle 15 is half the measure of arc ES, so is 40°/2 = 20°.

Angle 16 is vertical to the remaining interior angle of the triangle containing angles 14 and 15. Its measure is 180° -72.5° -20° = 87.5°.

Angle 17 is half the sum of arcs ES and OH, so is (40° +115°)/2 = 77.5°.

Angle 18 is half the measure of arc RN, so is (30° +40°)/2 = 35°.

Angle 19 is half the sum of arcs LR and EW, so is (20° +130°)/2 = 75°.

Angle 20 is half the measure of arc HN, so is 40°/2 = 20°.

Angle 21 is complementary to angle 1, so is (90° -40°) = 50°.

Angle 22 is the remaining interior angle of triangle ACE, so is (180° -35° -50°) = 95°.

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