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3 years ago

Find the surface area of a grapefruit with a circumference of 14 cm. Round your answer to the nearest whole number.

Mathematics

2 answers:

aleksklad [387]3 years ago

7 0

I just took the test the answer is 62 cm ^2

Maru [420]3 years ago

3 0

The answer is 62 cm^2!

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Thats my question down there mates

Law Incorporation [45]

Answer:

x = 9

Step-by-step explanation:

A line segment parallel to a side of a triangle and intersecting the other 2 sides divides the 2 sides in proportion, that is

$\frac{9}{72}$ = $\frac{1}{8}$ = $\frac{3x-20}{56}$ ( cross- multiply )

8(3x - 20) = 56

24x - 160 = 56 ( add 160 to both sides )

24x = 216 ( divide both sides by 24 )

x = 9

7 0

3 years ago

Read 2 more answers

the marks in an examination for a Physics paper have normal distribution with mean μ and variance σ2 . 10% of the students obtai

Blababa [14]

Let $X$ be the random variable for the number of marks a given student receives on the exam.

10% of students obtain more than 75 marks, so

$P(X>75)=P\left(\dfrac{X-\mu}\sigma>\dfrac{75-\mu}\sigma\right)=P(Z>z_1)=0.10$

where $Z$ follows a standard normal distribution. The critical value for an upper-tail probability of 10% is

$P(Z>z_1)=1-F_Z(z_1)=0.10\implies z_1=F_Z^{-1}(0.90)$

where $F_Z(z)=P(Z\le z)$ denotes the CDF of $Z$ , and $F_Z^{-1}$ denotes the inverse CDF. We have

$z_1=F_Z^{-1}(0.90)\approx1.2816$

Similarly, because 20% of students obtain less than 40 marks, we have

$P(X$

so that

$P(Z$

Then $\mu,\sigma$ are such that

$\dfrac{75-\mu}\sigma\approx1.2816\implies75\approx\mu+1.2816\sigma$

$\dfrac{40-\mu}\sigma\approx-0.8416\implies40\approx\mu-0.8416\sigma$

and we find

$\mu\approx53.8739,\sigma\approx16.4848$

3 0

4 years ago

Ronnie and Angela went to the pizza shop and each bought a medium pizza. Angela cut her pizza into four pieces and ate three of

Luden [163]

Answer: there is nothing shown below

Step-by-step explanation:

3 0

3 years ago

A total of 815 tickets were sold for the school play. They were either adult tickets or student tickets. There were 65 more stud

kvv77 [185]

Answer:

375 Adult Tickets.

Step-by-step explanation:

Here, we can simply set up an equation using variable x in place of the unknown student/adult tickets.

x = # of adult tickets sold

x + 65 = # of student tickets sold.

1) x + x + 65 = 815 (set both ticket amounts equal to the total)

2) 2x + 65 = 815 (added common variables together)

3) 2x = 750 (negated the +65, subtracted it from both sides)

4) x = 375 (divided both sides by 2)

5) 815 - 375 = 440 (subtracted the x from the total number of adult tickets, to recieve the amount of childrens' tickets.

Therefore,

Since there were fewer adult tickets sold (-65), 375 is the number of adult tickets, and 440 is the number of student tickets.

5 0

2 years ago

Mathematics pls help me.

uysha [10]

Answer:

I think the answer may be 465

Step-by-step explanation:

105+115=220

150+95=245

245+220=465

8 0

3 years ago