Question

What is the square root of 18y over 36y to the third power? - I need to show work!

Answer 1

$\sqrt{\dfrac{18y}{36y^3}}=\sqrt{\dfrac{18y}{18y\cdot2y^2}}=\sqrt{\dfrac{1}{2y^2}}=\dfrac{\sqrt1}{\sqrt{2y^2}}=\dfrac{1}{\sqrt2\cdot\sqrt{y^2}}=\dfrac{1}{y\sqrt2}$

$\dfrac{1}{y\sqrt2}=\dfrac{1}{y\sqrt2}\cdot\dfrac{\sqrt2}{\sqrt2}=\dfrac{\sqrt2}{2y}$