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MrRissso [65]
3 years ago
8

How many solutions does this linear system of equations have?

Mathematics
1 answer:
kotegsom [21]3 years ago
3 0

Answer:

3x=y-3

Step-by-step explanation:

-3x+y=4

-4+y=hu

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I need to know how I got number 27 because I can’t remember what I did
krok68 [10]
B=75, not 27
Sorry, I had to use a napkin because I was too lazy to get a paper....let me know if u need me to explain anything

4 0
3 years ago
Juan decided to start saving for college. He deposited $500 into an account which earns 4% simple annual interest. At the end of
Norma-Jean [14]

Answer:

$5504

Step-by-step explanation:

Given that :

Principal amount = $500

Interest = 4% simple interest annually

Amount added at the end of each year :

First year:

Principal + (Principal * rate * time)

500 + (500 * 0.04) = 520

$520 + $250 = $770

2nd year:

770 + (770 * 0.04) = $800.80

$800.80 + $250 = 1050.80

3rd year:

1050.8 + (1050.8 * 4) = 5254

$5254 + 250 = $5504

5 0
3 years ago
There are 614,952 pepole living in a city round this number ot the nearest thousand
Dima020 [189]

Answer:

615,000

Step-by-step explanation:

When you "round to the nearest _____" regardless of what goes in the blank the steps are nearly always the same:

Identify which place value you are rounding to. The smaller the place value, the more accurate the final result will be.

Look to the next smallest place value, the digit to the right of the place value you're rounding to. For example, if you want to round to the nearest ten you'd look at the ones place.

If the digit in the next smallest place value is less than five (0, 1, 2, 3, or 4), you leave the digit you want to round to as-is. Any digits after that number (including the next smallest place value you just looked at) become zeros, or drop-off if they're located after the decimal point. This is called rounding down.

If the next smallest place value is greater than or equal to five (5, 6, 7, 8, or 9), you increase the value of the digit you're rounding to by one (+1). Just like before, any remaining digits before the decimal point become zeros, and any that are after the decimal point are dropped. This is called rounding up.

3 0
3 years ago
Read 2 more answers
You are driving due north on the highway. Ahead, but off to the East, you see a tall tower. Sketch a graph or make a table showi
valentina_108 [34]

Answer:

The amount of speed you go will determine the graph but it should go closer and closer but then farther away because you drive past the tower

Step-by-step explanation:

3 0
3 years ago
How is this solved using trig identities (sum/difference)?
GenaCL600 [577]
FIRST PART
We need to find sin α, cos α, and cos β, tan β
α and β is located on third quadrant, sin α, cos α, and sin β, cos β are negative

Determine ratio of ∠α
Use the help of right triangle figure to find the ratio
tan α = 5/12
side in front of the angle/ side adjacent to the angle = 5/12
Draw the figure, see image attached

Using pythagorean theorem, we find the length of the hypotenuse is 13
sin α = side in front of the angle / hypotenuse
sin α = -12/13

cos α = side adjacent to the angle / hypotenuse
cos α = -5/13

Determine ratio of ∠β
sin β = -1/2
sin β = sin 210° (third quadrant)
β = 210°

cos \beta = -\frac{1}{2}  \sqrt{3}

tan \beta= \frac{1}{3}  \sqrt{3}

SECOND PART
Solve the questions
Find sin (α + β)
sin (α + β) = sin α cos β + cos α sin β
sin( \alpha + \beta )=(- \frac{12}{13} )( -\frac{1}{2}  \sqrt{3})+( -\frac{5}{13} )( -\frac{1}{2} )
sin( \alpha + \beta )=(\frac{12}{26}\sqrt{3})+( \frac{5}{26} )
sin( \alpha + \beta )=(\frac{5+12\sqrt{3}}{26})

Find cos (α - β)
cos (α - β) = cos α cos β + sin α sin β
cos( \alpha + \beta )=(- \frac{5}{13} )( -\frac{1}{2} \sqrt{3})+( -\frac{12}{13} )( -\frac{1}{2} )
cos( \alpha + \beta )=(\frac{5}{26} \sqrt{3})+( \frac{12}{26} )
cos( \alpha + \beta )=(\frac{5\sqrt{3}+12}{26} )

Find tan (α - β)
tan( \alpha - \beta )= \frac{ tan \alpha-tan \beta }{1+tan \alpha  tan \beta }
tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3}   }{1+(\frac{5}{12}) ( \frac{1}{2} \sqrt{3})}

Simplify the denominator
tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3}   }{1+(\frac{5\sqrt{3}}{24})}
tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3} }{ \frac{24+5\sqrt{3}}{24} }

Simplify the numerator
tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{6}{12} \sqrt{3} }{ \frac{24+5\sqrt{3}}{24} }
tan( \alpha - \beta )= \frac{ \frac{5-6\sqrt{3}}{12} }{ \frac{24+5\sqrt{3}}{24} }

Simplify the fraction
tan( \alpha - \beta )= (\frac{5-6\sqrt{3}}{12} })({ \frac{24}{24+5\sqrt{3}})
tan( \alpha - \beta )= \frac{10-12\sqrt{3} }{ 24+5\sqrt{3}}

7 0
2 years ago
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