Answer:
2
Step-by-step explanation:
8 times 1/4 equals 2
if this is wrong i am so sorry
Answer:
6, 8, and 10.
Step-by-step explanation:
You could work this out with the pythagorean theorem, by proving that 6^2, 36, plus 8^2, 64, equals 100. The fastest way, however, is to use pythagorean triples. These are predetermined sets of numbers that work as side lengths for right triangles. The first two are 3, 4, and 5, which form a right triangle, and 6, 8, and 10, shown here.
Both elevations or numbers are already expressed as a
rational number. This is because a rational number is defined as a number that
can be expressed as a quotient or fraction of two numbers:
p / q
Since in this case, q may be equal to 1, then both are
rational numbers.
If i'm mistaken; he needs to buy 3 sheets?
Use the equation and type the ordered-pairs. y = log 3 x {(1/3, a0), (1, a1), (3, a2), (9, a3), (27, a4), (81, a5)
vagabundo [1.1K]
Answer:
Considering the given equation ![y = log_{3}x\\](https://tex.z-dn.net/?f=y%20%3D%20log_%7B3%7Dx%5C%5C)
And the ordered pairs in the format ![(x, y)](https://tex.z-dn.net/?f=%28x%2C%20y%29)
I don't know if it is log of base 3 or 10, but I will assume it is 3.
For ![(\frac{1}{3}, a_{0} )](https://tex.z-dn.net/?f=%28%5Cfrac%7B1%7D%7B3%7D%2C%20a_%7B0%7D%20%29)
![y=a_{0}](https://tex.z-dn.net/?f=y%3Da_%7B0%7D)
![y = log_{3}x\\y = log_{3}(\frac{1}{3} )\\y=-\log _3\left(3\right)\\y=-1](https://tex.z-dn.net/?f=y%20%3D%20log_%7B3%7Dx%5C%5Cy%20%3D%20log_%7B3%7D%28%5Cfrac%7B1%7D%7B3%7D%20%29%5C%5Cy%3D-%5Clog%20_3%5Cleft%283%5Cright%29%5C%5Cy%3D-1)
So the ordered pair will be ![(\frac{1}{3}, -1 )](https://tex.z-dn.net/?f=%28%5Cfrac%7B1%7D%7B3%7D%2C%20-1%20%29)
For ![(1, a_{1} )](https://tex.z-dn.net/?f=%281%2C%20a_%7B1%7D%20%29)
![y=a_{1}](https://tex.z-dn.net/?f=y%3Da_%7B1%7D)
![y = log_{3}x\\y = log_{3}1\\y = log_{3}(1)\\Note: \log _a(1)=0\\y = 0](https://tex.z-dn.net/?f=y%20%3D%20log_%7B3%7Dx%5C%5Cy%20%3D%20log_%7B3%7D1%5C%5Cy%20%3D%20log_%7B3%7D%281%29%5C%5CNote%3A%20%5Clog%20_a%281%29%3D0%5C%5Cy%20%3D%200)
So the ordered pair will be ![(1, 0 )](https://tex.z-dn.net/?f=%281%2C%200%20%29)
For ![(3, a_{2} )](https://tex.z-dn.net/?f=%283%2C%20a_%7B2%7D%20%29)
![y=a_{2}](https://tex.z-dn.net/?f=y%3Da_%7B2%7D)
![y = log_{3}x\\y = log_{3}3\\y = 1](https://tex.z-dn.net/?f=y%20%3D%20log_%7B3%7Dx%5C%5Cy%20%3D%20log_%7B3%7D3%5C%5Cy%20%3D%201)
So the ordered pair will be ![(3, 1 )](https://tex.z-dn.net/?f=%283%2C%201%20%29)
For ![(9, a_{3} )](https://tex.z-dn.net/?f=%289%2C%20a_%7B3%7D%20%29)
![y=a_{3}](https://tex.z-dn.net/?f=y%3Da_%7B3%7D)
![y = log_{3}x\\y = log_{3}9\\y=2\log _3\left(3\right)\\y=2](https://tex.z-dn.net/?f=y%20%3D%20log_%7B3%7Dx%5C%5Cy%20%3D%20log_%7B3%7D9%5C%5Cy%3D2%5Clog%20_3%5Cleft%283%5Cright%29%5C%5Cy%3D2)
So the ordered pair will be ![(9, 2 )](https://tex.z-dn.net/?f=%289%2C%202%20%29)
For ![(27, a_{4} )](https://tex.z-dn.net/?f=%2827%2C%20a_%7B4%7D%20%29)
![y=a_{4}](https://tex.z-dn.net/?f=y%3Da_%7B4%7D)
![y = log_{3}x\\y = log_{3}27\\y=3\log _3\left(3\right)\\y=3](https://tex.z-dn.net/?f=y%20%3D%20log_%7B3%7Dx%5C%5Cy%20%3D%20log_%7B3%7D27%5C%5Cy%3D3%5Clog%20_3%5Cleft%283%5Cright%29%5C%5Cy%3D3)
So the ordered pair will be ![(27, 3 )](https://tex.z-dn.net/?f=%2827%2C%203%20%29)
For ![(81, a_{5} )](https://tex.z-dn.net/?f=%2881%2C%20a_%7B5%7D%20%29)
![y=a_{5}](https://tex.z-dn.net/?f=y%3Da_%7B5%7D)
![y = log_{3}x\\y = log_{3}81\\y=4\log _3\left(3\right)\\y=4](https://tex.z-dn.net/?f=y%20%3D%20log_%7B3%7Dx%5C%5Cy%20%3D%20log_%7B3%7D81%5C%5Cy%3D4%5Clog%20_3%5Cleft%283%5Cright%29%5C%5Cy%3D4)
So the ordered pair will be ![(81, 4 )](https://tex.z-dn.net/?f=%2881%2C%204%20%29)