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Arturiano [62]
3 years ago
5

A fair coin is tossed and a single number cube is rolled. the probability of rolling a number less than 5 is ________________. t

he probability of flipping heads and rolling an odd number is _______________.
Mathematics
1 answer:
Alik [6]3 years ago
7 0
You have a 4/ 6 chance 
then you have a 2/6 chance if the number is an odd number then reducing you would get 
1.   2/3 
2.  1/3 
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5+x+(−2)=−85+x+(−2)=−8<br><br><br> x=?
sashaice [31]
5+x+(-2)=-85+x+(-2)=-8\\&#10;x-3=x-87=-8
x has no solution.
5 0
2 years ago
Find maclaurin series
Mumz [18]

Recall the Maclaurin expansion for cos(x), valid for all real x :

\displaystyle \cos(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n}}{(2n)!}

Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives

\displaystyle \cos\left(\sqrt 5\,x\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt5\,x\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^{2n}}{(2n)!}

The first 3 terms of the series are

\cos\left(\sqrt5\,x\right) \approx 1 - \dfrac{5x^2}2 + \dfrac{25x^4}{24}

and the general n-th term is as shown in the series.

In case you did mean cos(√(5x)), we would instead end up with

\displaystyle \cos\left(\sqrt{5x}\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt{5x}\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^n}{(2n)!}

which amounts to replacing the x with √x in the expansion of cos(√5 x) :

\cos\left(\sqrt{5x}\right) \approx 1 - \dfrac{5x}2 + \dfrac{25x^2}{24}

7 0
2 years ago
The sum of a rational number and negative integer is rational
natulia [17]

Answer:

correct

Step-by-step explanation:

negative integers are still rational numbers if it is a whole number or complete

4 0
3 years ago
What is are SLOPE and EQUATION of the image?
zepelin [54]

Answer:

3

y=3x

Step-by-step explanation:

y=mx+b

y=3x+0

y=3x

8 0
3 years ago
Solve for r: i=prt<br> please help
babymother [125]

Answer:

hmm

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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