Answer:
1/8
Explanation:
Given that the trihybrid parents have AaBbCc genotype for fruit color. The trait is a quantitative trait i.e. each dominant allele will have an additive effect on it. In this case, AaBbCc and AABBCC will not produce same fruit color because AaBbCc has only three loci contributing to the color while in AABBCC all the six loci are contributing to the color. For an offspring to be exactly similar to the AaBbCc parents it should have the same genotype of AaBbCc.
The probability of Aa to come from a cross between Aa and Aa is 2/4 or 1/2
The probability of Bb to come from a cross between Bb and Bb is 2/4 or 1/2
The probability of Cc to come from a cross between Cc and Cc is 2/4 or 1/2
So the collective probability of AaBbCc offspring from a cross between AaBbCc and AaBbCc parents would be=
1/2 * 1/2 * 1/2 = 1/8
Hence, assuming no effects of the environment, 1/8 of the offspring will have the same fruit color phenotype as the trihybrid parent.
Coal from swamp plants that formed millions of years ago.
Answer:
The correct answer would be B. thrombocytes.
Thrombocytes, also called platelets are the components of the blood which play important role in the process of hemostasis.
Hemostasis is the process of preventing the flow of blood from the damaged site or damaged blood vessel. It is the first stage involved in the healing of the wound.
Platelets form the platelet-plug at the site of damage which in turn activates another blood clotting factor fibrinogen.
Fibrinogen gets converted into an active fibrin (insoluble) which forms the meshwork like structure to trap more and more platelets and red blood cells. It results in the formation of a clot which completely seals the cut or damaged site.
