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kobusy [5.1K]
3 years ago
15

What is the value of x? Enter your answer in the box. x = NOTE: Image not drawn to scale. Triangle G E H with segment E D such t

hat D is on segment G H, between G and H. Angle G E D is congruent to angle D E H. E G = 49 cm, G D =35 cm, D H equals (x + 1) cm, and E H= 58.8 cm.

Mathematics
2 answers:
GrogVix [38]3 years ago
5 0

Answer:


Step-by-step explanation:

Given is a triangle EGH with sides 49, 58.8 cm and third side as two parts with 35 and x+1 cm.

We have to find x.

Consider triangle GED and EDH separately.  We use sine formula to find GD and HD


Use sine formula for triangles

\frac{35}{sinGED} =\frac{49}{sinGDE} \\\frac{x+1}{sinDEH}=\frac{58.8}{sinEDH}  \\

But sin GED = sin DEH (angle bisector)

Sin GDE = sin EDH (supplementary angles have the same sine)

So 35/49 = (x+1)/58.8

5/9=x+1/58.8

294 =9x+9

285 =9x

x =285/9 = 95/3

= 31.33 cm.

shtirl [24]3 years ago
4 0

Answer:

The answer is (41)

Step-by-step explanation:

I just took the test

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Dmitrij [34]

Answer:

y = \frac{1}{4} x - 5

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) =( 8, - 3) and (x₂, y₂ ) = (0, - 5)

m = \frac{-5+3}{0-8} = \frac{-2}{-8} = \frac{1}{4}

Note the line crosses the y- axis at (0, - 5 ) ⇒ c = - 5

y = \frac{1}{4} x - 5 ← equation of line

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4 years ago
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GarryVolchara [31]

Answer:

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

Step-by-step explanation:

Check for conditions

For this case in order to use the normal distribution for this case or the 68-95-99.7% rule we need to satisfy 3 conditions:

a) Independence : we assume that the random sample of 400 students each student is independent from the other.

b) 10% condition: We assume that the sample size on this case 400 is less than 10% of the real population size.

c) np= 400*0.74= 296>10

n(1-p) = 400*(1-0.74)=104>10

So then we have all the conditions satisfied.

Solution to the problem

For this case we know that the distribution for the population proportion is given by:

p \sim N(p, \sqrt{\frac{p(1-p)}{n}})

So then:

\mu_p = 0.74

\sigma_p =\sqrt{\frac{0.74(1-0.74)}{400}}=0.0219

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

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Answer:

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Step-by-step explanation:

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