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Ne4ueva [31]
3 years ago
11

I don’t know how to solve this

Mathematics
2 answers:
Olin [163]3 years ago
8 0

\frac{y - y1}{y2 - y1} =  \frac{x - x1}{x2 - x1}   \\  \frac{y - ( - 3)}{ - 5 - ( - 3)}  =  \frac{x - 8}{0 - 8}  \\  \frac{y + 3}{ - 2}  =  \frac{x - 8}{ - 8}  \\  - 8(y + 3) =  - 2(x - 8) \\  - 8y  - 24 =  - 2x + 16 \\ 2x - 8y = 40

Dmitrij [34]3 years ago
4 0

Answer:

y = \frac{1}{4} x - 5

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) =( 8, - 3) and (x₂, y₂ ) = (0, - 5)

m = \frac{-5+3}{0-8} = \frac{-2}{-8} = \frac{1}{4}

Note the line crosses the y- axis at (0, - 5 ) ⇒ c = - 5

y = \frac{1}{4} x - 5 ← equation of line

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7. Quadrilateral MNPQ has vertices M(4,0), N(0,6), P(-4,0) and Q(0, -6). Determine whether
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Answer:

SQUARE

Step-by-step explanation:

If Quadrilateral MNPQ has vertices M(4,0), N(0,6), P(-4,0) and Q(0, -6).

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Using the formula for calculating the distance between two points

MN = √(6-0)²+(0-4)²

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NP = √(0-6)²+(-4-0)²

NP = √6²+4²

NP = √36+16

NP = √52

NP = 2√13

PQ = √(-6-0)²+(0-(-4))²

PQ = √6²+4²

PQ = √36+16

PQ = √52

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MQ = √(-6-0)²+(0-4)²

MQ = √6²+4²

MQ = √36+16

MQ= √52

MQ = 2√13

Since the length of all the sides are equal, hence the shape is a SQUARE

4 0
2 years ago
Find AuB and AnB for the sets A and B.<br> A={3, 4, 5, 6, 7), B = {4, 6, 8, 10)
kvv77 [185]

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7 0
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Step-by-step explanation:

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3 years ago
PLEASE ANSWER QUICKLY
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