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jeka94
3 years ago
12

2. Mr. Penman had 2/3 liter of salt water. He used 1/5 of a liter for an experiment. How much salt water does Mr. Penman have le

ft?
Mathematics
1 answer:
Tems11 [23]3 years ago
4 0

Answer:

7/15

Step-by-step explanation:

Simplify the terms:

  • \frac{2}{3}=\frac{10}{15}
  • \frac{1}{5}=\frac{3}{15}

Combine the terms:

  • \frac{10}{15}-\frac{3}{15}=\frac{7}{15}

Therefore, the total of salt water would be left would be 7/15..

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After six hours, the bright, hot sun became unbearable.

Right answer ^^^^
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3 years ago
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Find the slope of the line that passes through the points (5, 8) and (9, 4).
Alja [10]
Y2 - y1/x2 - x1 = slope

4 - 8/ 9 - 5 = slope

-4/4 = slope

-1 = slope

hope this helps :)

3 0
4 years ago
What is the unit rate of y=0.75x
Elodia [21]
The unit rate is 0.75
7 0
3 years ago
PLS HELP MEEE I WILL GIVE BRAINLY THINGY
Ierofanga [76]

Answer:

125

Step-by-step explanation:

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25 x 5 = 125

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3 years ago
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The rates of on-time flights for commercial jets are continuously tracked by the U.S. Department of Transportation. Recently, So
tatyana61 [14]

Answer:

The probability that at least 13 flights arrive late is 2.5196 \times 10^{-6}.

Step-by-step explanation:

We are given that Southwest Air had the best rate with 80 % of its flights arriving on time.

A test is conducted by randomly selecting 18 Southwest flights and observing whether they arrive on time.

The above situation can be represented through binomial distribution;

P(X = x) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,.........

where, n = number of trials (samples) taken = 18 Southwest flights

           r = number of success = at least 13 flights arrive late

          p = probability of success which in our question is probability that

                flights arrive late, i.e. p = 1 - 0.80 = 20%

Let X = <u><em>Number of flights that arrive late</em></u>.

So, X ~ Binom(n = 18, p = 0.20)

Now, the probability that at least 13 flights arrive late is given by = P(X \geq 13)

P(X \geq 13) = P(X = 13) + P(X = 14) + P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18)

= \binom{18}{13}\times 0.20^{13} \times (1-0.20)^{18-13}+ \binom{18}{14}\times 0.20^{14} \times (1-0.20)^{18-14}+ \binom{18}{15}\times 0.20^{15} \times (1-0.20)^{18-15}+ \binom{18}{16}\times 0.20^{16} \times (1-0.20)^{18-16}+ \binom{18}{17}\times 0.20^{17} \times (1-0.20)^{18-17}+ \binom{18}{18}\times 0.20^{18} \times (1-0.20)^{18-18}

= \binom{18}{13}\times 0.20^{13} \times 0.80^{5}+ \binom{18}{14}\times 0.20^{14} \times 0.80^{4}+ \binom{18}{15}\times 0.20^{15} \times 0.80^{3}+ \binom{18}{16}\times 0.20^{16} \times 0.80^{2}+ \binom{18}{17}\times 0.20^{17} \times 0.80^{1}+ \binom{18}{18}\times 0.20^{18} \times 0.80^{0}

= 2.5196 \times 10^{-6}.

7 0
3 years ago
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