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jeka94
2 years ago
12

2. Mr. Penman had 2/3 liter of salt water. He used 1/5 of a liter for an experiment. How much salt water does Mr. Penman have le

ft?
Mathematics
1 answer:
Tems11 [23]2 years ago
4 0

Answer:

7/15

Step-by-step explanation:

Simplify the terms:

  • \frac{2}{3}=\frac{10}{15}
  • \frac{1}{5}=\frac{3}{15}

Combine the terms:

  • \frac{10}{15}-\frac{3}{15}=\frac{7}{15}

Therefore, the total of salt water would be left would be 7/15..

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Solve 0.7(5x+15)=2.9-(x+3)
Anni [7]
0.7(5x+15)=2.9 -(x+3)
3.5x+10.5=2.9-x-3
3.5x+10.5= -0.1- x
4.5x= -10.6
x= -2.3555...

Check:
0.7(5(-2.3555...) +15) = 2.9 -(x+3)
2.2555... = 2.2555...
6 0
3 years ago
Lisa is 10 cm taller than her friend ian. Ian is 14 cm taller than jim. Every month, their heights increase by 2 cm. In 7 months
koban [17]

Answer:  Ian's height = x+14 = 69+14 = 83 cm

Explanation :

Let the height of Jim be x

Let the  height of Ian be x+4

Let the height of Lisa be x+4+10=x+14

Since their heights increase by 2cm every months

so after 7 months ,

Jim's  height = x+14

Ian's  height= x+4+14=x+18

Lisa's  height= x+14+14=x+28

According to question,

Sum of Ian's and Jim's height = 170cm

x+18+x+14 = 170\\2x+32 =170\\2x =170-32\\2x = 138

⇒x = \frac{138}{2}

⇒ x= 69cm

∴ Ian's height = x+14 = 69+14 = 83 cm

5 0
3 years ago
Read 2 more answers
In the table, hoe many cups of flour would you need to make 90 cookies? Graph the relationship below
-Dominant- [34]
Not sure what we need to do for this question, as it appears that you have already completed it, but looking over your answer, the graphed relationship looks correct! And it would take 3 cups of flour to make 90 cookies, as per the table.
3 0
3 years ago
Simplify the expression (1/x^2 + 2/y)/(5/x - 6/y^2)
ozzi

Answer:

y(y+2x^2)/x(5y^2-6x)

Step-by-step explanation:

7 0
3 years ago
Let fx) = 8x-3<br> What is (5)?<br> O A. 40<br> O B. 37<br> O C. 45<br> O D. 43
saveliy_v [14]

Answer:

I'm not sure i think B. 37

Step-by-step explanation:

f(x) = 8x-3

f(5)= 8(5)-3

40-3=37

8 0
3 years ago
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