Answer:
Small scooters = 6
Large scooters = 4
Step-by-step explanation:
Let S represents small scooter and L represents large scooter
The cost of a small scooter is £80
Mathematically, the cost of S number of small scooters is
80S
The cost of a large scooter is £130
Mathematically, the cost of L number of large scooters is
130L
The total amount spent on both scooters is £1000
Mathematically,
80S + 130L = 1000
So we have 2 unknowns and only 1 equation. Therefore, we have use trial and error method
.
Trial and Error Method:
80S + 130L = 1000
80S = 1000 - 130L
S = (1000 - 130L)/80
Let’s suppose they bought 1 large scooter
S = (1000 - 130(1))/80
S = 10.875
Number of scooters cannot be in fraction so 1 doesn’t work
Let’s suppose they bought 2 large scooter
s
S = (1000 - 130(2))/80
S = 9.25
Number of scooters cannot be in fraction so 2 doesn’t work
Let’s suppose they bought 3 large scooter
s
S = (1000 - 130(3))/80
S = 7.625
Number of scooters cannot be in fraction so 3 doesn’t work
Let’s suppose they bought 4 large scooters
S = (1000 - 130(4))/80
S = 6
So that means they bought 6 small scooters and 4 large scooters.
Similarly, other combinations for scooters don’t work since they yield either fractional value or negative value which cannot be correct.
Therefore, the only possible combination of small and large scooters is
6 Small scooters
4 Large scooters
Verification:
80S + 130L = 1000
80(6) + 130(4) = 1000
480 + 520 = 1000
1000 = 1000 (satisfied)
r^2. If you insert the first equation into this equation you will got: