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inn [45]
3 years ago
12

McKinley is 10 years less than half as old as Thomas. The sum of their age is 53. How old is each

Mathematics
2 answers:
GREYUIT [131]3 years ago
7 0
M=1/2T-10
M+T= 53 M=53-T
53-T=1/2T-10
63=3/2T 63*(2/3)=42=T
M=(1/2)*42-10=11
M=11
ohaa [14]3 years ago
4 0

Answer:

lll

Step-by-step explanation:

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EASY Work!! Please look at the picture and yes it’s easy for other people but not me for people asking.
Keith_Richards [23]

Answer:

7()=11

8()=42

I could barely see the answer for number 9 sorry :(

Step-by-step explanation:

the 7() is 2(3)+5

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Question (8)

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Solve y = x + 6 for x.
elena-s [515]

Answer:

C

Step-by-step explanation:

move the x over

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4 0
2 years ago
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What is the value of 3(y + 4) – (x – 1) when x = 3 and y = 2
olga_2 [115]

Answer:

16

Step-by-step explanation:

First, substitute the values of the variables into the expression:

3(y + 4) - (x - 1)

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7 0
3 years ago
(ASAP PICTURE ADDED) What is the simplified form of the following expression?
bonufazy [111]

Answer:

option c is correct.

Step-by-step explanation:

7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{16x}\right)-3\left(\sqrt[3]{8x}\right)

WE need to simplify this equation.

Solve the parenthesis of each term.

=7\left\sqrt[3]{2x}\right-3\left\sqrt[3]{16x}\right-3\left\sqrt[3]{8x}\right

Now, We will find factors of the terms inside the square root

factors of 2: 2

factors of 16 : 2x2x2x2

factors of 8: 2x2x2

Putting these values in our equation:=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2X2 x}\right)-3\left(\sqrt[3]{2X2X2 x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3*2\left(\sqrt[3] {2 x}\right)-3*2\left(\sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2}\sqrt[3]{x}\right)-6\left(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)

Adding like terms we get:

=7\left(\sqrt[3]{2}\sqrt[3]{x}\right)-6\left(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right\\=(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)\\

(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)\\can\,\,be \,\, written\,\, as\,\,\\(\sqrt[3] {2x})-6\left(\sqrt[3]{x}\right)

So, option c is correct

5 0
3 years ago
Read 2 more answers
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