How to find the slope of (20/8) and (9,16)?

Pleasee help me find the slope

BlackZzzverrR [31]

Answer:

The slope is m=1/2

Step-by-step explanation:

hope this helps you.

7 0

3 years ago

In a volleyball game, a player on one team spikes the ball over the net when the ball is 8 feet above the court. The spike drive

Fofino [41]

Answer:

.173 seconds or a negataive

Step-by-step explanation:

Your formula would be

h = -16t^2 - 55t + 10

when it hits the ground h = 0

16t^2 + 55t - 10 = 0

t = (-55 ± √3665)/32 = .173 seconds or a negataive

6 0

3 years ago

Find x y and z in this probelm

marishachu [46]

For the top shape, x = 11, y = 10 and z = 14.

Start with the equation: 11y + 7y = 180 because those two angles are supplementary. Solving that will give you that y = 10.

The angle that is labelled 7y is therefore 70 degrees. We can write the following equation will the 5x because it is corresponding to the 70 degree angle.

5z = 70
z = 14

And we can also write and solve for the x, using the 70 degree angle.
70 + 10x = 180
10x = 110
x = 11

5 0

4 years ago

The square root of a2+1=2

user100 [1]

Remove the radical by raising each side to the index of the radical. a = √ 3 , − √ 3 a=3,-3 a ≈ 1.73205080 , − 1.73205080

7 0

4 years ago

Each item produced by a certain manufacturer is independently of acceptable quality with probability 0.95. Approximate the proba

Diano4ka-milaya [45]

Answer:

The probability that at most 10 of the next 150 items produced are unacceptable is 0.8315.

Step-by-step explanation:

Let X = number of items with unacceptable quality.

The probability of an item being unacceptable is, P (X) = p = 0.05.

The sample of items selected is of size, n = 150.

The random variable X follows a Binomial distribution with parameters n = 150 and p = 0.05.

According to the Central limit theorem, if a sample of large size (n > 30) is selected from an unknown population then the sampling distribution of sample mean can be approximated by the Normal distribution.

The mean of this sampling distribution is: $\mu_{\hat p}= p=0.05$

The standard deviation of this sampling distribution is: $\sigma_{\hat p}=\sqrt{\frac{ p(1-p)}{n}}=\sqrt{\frac{0.05(1-.0.05)}{150} }=0.0178$

If 10 of the 150 items produced are unacceptable then the probability of this event is:

$\hat p=\frac{10}{150}=0.067$

Compute the value of $P(\hat p\leq 0.067)$ as follows:

$P(\hat p\leq 0.067)=P(\frac{\hat p-\mu_{p}}{\sigma_{p}} \leq\frac{0.067-0.05}{0.0178})=P(Z\leq 0.96)=0.8315$

*Use a z-table for the probability.

Thus, the probability that at most 10 of the next 150 items produced are unacceptable is 0.8315.

5 0

3 years ago