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3 years ago

State whether the lines are parallel, perpendicular,or neither.

Mathematics

1 answer:

cluponka [151]3 years ago

8 0

Answer:

Please check the explanation.

Step-by-step explanation:

Two lines are parallel if their slopes are equal.

Two lines are perpendicular if the product of their slope is -1

We also know that the slope-intercept form of the line equation is

$y=mx+b$

where m is the slope and b is the y-intercept

Given the lines

y = 6х - 3

Comparing with y=mx+b, the slope of y = 6х - 3:

m₁=6

y = - 1/6x + 7

Comparing with y=mx+b, the slope of y = - 1/6x + 7:

m₂=-1/6

m₁ × m₂ = -1

6 × - 1/6 = -1

-1 = -1

Thus, the lines y = 6х - 3 and y = - 1/6x + 7 are perpendicular.

y = 3x + 2

Comparing with y=mx+b, the slope of y = 3x + 2:

m₁=3

2y = 6x - 6

simplifying to write in slope-intercept form

y=3x-3

Comparing with y=mx+b, the slope of y=3x-3:

m₂=3

As the slopes of y = 3x + 2 and 2y = 6x - 6 are equal.

i.e. m₁ = m₂ → 3 = 3

Thus, the lines y = 3x + 2 and 2y = 6x - 6 are paralle.

8x - 2y = 3

simplifying to write in slope-intercept form

y = 4x - 3/2

Comparing with y=mx+b, the slope of y = 4x - 3/2:

m₁=4

x + 4y = - 1

simplifying to write in slope-intercept form

y=-1/4x-1/4

Comparing with y=mx+b, the slope of y=-1/4x-1/4:

m₂=-1/4

m₁ × m₂ = -1

4 × - 1/4 = -1

-1 = -1

Thus, the lines 8x - 2y = 3 and x + 4y = - 1 are perpendicular.

3x+2y = 5

simplifying to write in slope-intercept form

y = -3/2x + 5/2

Comparing with y=mx+b, the slope of y = -3/2x + 5/2:

m₁=-3/2

3y + 2x = - 3

simplifying to write in slope-intercept form

y = -2/3x - 1

Comparing with y=mx+b, the slope of y = -2/3x - 1:

m₂=-2/3

As m₁ and m₂ are neither equal nor their product is -1, hence the lines neither perpendicular nor parallel.

y - 5 = 6x

simplifying to write in slope-intercept form

y=6x+5

Comparing with y=mx+b, the slope of y=6x+5:

m₁=6

y - 6x = - 1

simplifying to write in slope-intercept form

y=6x-1

Comparing with y=mx+b, the slope of y=6x-1:

m₂=6

As the slopes of y - 5 = 6x and y - 6x = -1 are equal.

i.e. m₁ = m₂ → 6 = 6

Thus, the lines y - 5 = 6x and y - 6x = -1 are paralle.

y = 3х + 9

Comparing with y=mx+b, the slope of y = 3х + 9:

m₁=3

y = -1/3x - 4

Comparing with y=mx+b, the slope of y = 1/3x - 4:

m₂=1/3

As m₁ and m₂ are neither equal nor their product is -1, hence the lines neither perpendicular nor parallel.

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App 19.study

lions [1.4K]

Answer:

$1 \to 22 \to 0.176$

$2 \to 13 \to 0.104$

$3 \to 18 \to 0.144$

$4 \to 29 \to 0.232$

$5 \to 37 \to 0.296$

$6 \to 6 \to 0.048$

Step-by-step explanation:

Given

$n = 125$

See attachment for proper table

Required

Complete the table

Experimental probability is calculated as:

$Pr = \frac{Frequency}{n}$

We use the above formula when the frequency is known.

For result of roll 2, 4 and 6

The frequencies are 13, 29 and 6, respectively

So, we have:

$Pr(2) = \frac{13}{125} = 0.104$

$Pr(4) = \frac{29}{125} = 0.232$

$Pr(6) = \frac{6}{125} = 0.048$

When the frequency is to be calculated, we use:

$Pr = \frac{Frequency}{n}$

$Frequency = n * Pr$

For result of roll 3 and 5

The probabilities are 0.144 and 0.296, respectively

So, we have:

$Frequency(3) = 125 * 0.144 = 18$

$Frequency(5) = 125 * 0.296 = 37$

For roll of 1 where the frequency and the probability are not known, we use:

$Total \ Frequency = 125$

So:

Frequency(1) added to others must equal 125

This gives:

$Frequency(1) + 13 + 18 + 29 + 37 + 6 = 125$

$Frequency(1) + 103 = 125$

Collect like terms

$Frequency(1) =- 103 + 125$

$Frequency(1) =22$

The probability is then calculated as:

$Pr(1) = \frac{22}{125}$

$Pr(1) = 0.176$

So, the complete table is:

$1 \to 22 \to 0.176$

$2 \to 13 \to 0.104$

$3 \to 18 \to 0.144$

$4 \to 29 \to 0.232$

$5 \to 37 \to 0.296$

$6 \to 6 \to 0.048$

5 0

3 years ago

The area of the triangle is 42 square inches. find the value of x when a = x and b = (x+8)

damaskus [11]

Answer:

6 and -14

Step-by-step explanation:

Area of the triangle = 1/2 ab

42 = 1/2 (x)(x+8)

42 *2 = x(x+8)

84 = x²+8x

x²+8x-84 = 0

x²+14x-6x-84 = 0

x(x+14)-6(x+14) = 0

x-6 = 0 and x+14 = 0

x = 6 and -14

Hence the values of x are 6 and -14

3 0

3 years ago

A lawyer has found 60 investors for a limited partnership to purchase an inner-city apartment building, with each contributing e

Mars2501 [29]

Answer:

1. The lawyer has 34 investors that contribute with $3,000 and has 26 investors that contribute with $6,000.

2. The jar has 26 nickels and 44 dimes that worth $5.70.

3. The concession stand has sold 1600 sodas and 1400 hotdogs

Step-by-step explanation:

For all the problems we are going to follow the same process that will consist on 1. Define the variables. 2. Formulate the system of two linear equations 3. Solve by the elimination method 4. Give the answer.

First problem.

- Variables:

x = number of investors that contribute with $3,000

y = number of investors that contribute with $6,000

- System of equations.

First equation will be the result of adding the number of investors that will give us a total of 60 investors then:

x + y = 60

Second equation is the result of multypling the number of investors by its invest and adding between them to get the $258,000 they have raised:

3,000x + 6,000y = 258,000

The system will be:

x + y = 60

3,000x + 6,000y = 258,000

- Solve by the elimination method.

To cancel x we are going to multiply by -3000 in both sides of the first equation and we will leave the second equation the same but in the first row to make easier the calculations then:

3,000x + 6,000y = 258,000

(x + y ) (-3,000) = 60 (-3,000) solve the multiplications

3,000x + 6,000y = 258,000

-3,000x - 3,000y = -180,000 solve the operations

0 + 3,000y = 78,000 clear y

$y = \frac{78,000}{3,000}$ solve the division

y = 26

For calculate x, replace the y value in the first equation and solve it

x + 26 = 60

x = 60 - 26

x = 34

- Answer

The lawyer has 34 investors that contribute with $3,000 and has 26 investors that contribute with $6,000.

Second problem

- Variables:

x = number of nickels

y = number of dimes

- System of equations.

First equation will be the result of adding the number of nickels and dimes that will give us a total of 70 coins in the jar then:

x + y = 70

Second equation is the result of multypling the number of coins by its value and adding between them to get the $5.70 that the jar worth:

0.05x + 0.1 y = 5.70

The system will be:

x + y = 70

0.05x + 0.1 y = 5.70

- Solve by the elimination method.

To cancel x we are going to multiply by -0.05 in both sides of the first equation and we will leave the second equation the same but in the first row to make easier the calculations then:

0.05x + 0.1 y = 5.70

(x + y ) (-0.05) = 70 (-0.05) solve the multiplications

0.05x + 0.1 y = 5.70

-0.05x - 0.05y = -3.50 solve the operations

0 + 0.05y = 2.20 clear y

$y = \frac{2.20}{0.05}$ solve the division

y = 44

For calculate x, replace the y value in the first equation and solve it

x + 44 = 70

x = 70 - 44

x = 26

- Answer

The jar has 26 nickels and 44 dimes that worth $5.70.

Third problem.

- Variables:

x = number of sodas sold by $2

y = number of hotdogs sold by $3

- System of equations.

First equation will be the result of adding the number of sodas and hotdogs that is of 3000 then:

x + y = 3000

Second equation is the result of multypling the number of sodas and hotdogs by its price and adding between them to get the $7400 of the receipts:

2x + 3y = 7400

The system will be:

x + y = 3000

2x + 3y = 7400

- Solve by the elimination method.

To cancel x we are going to multiply by -2 in both sides of the first equation and we will leave the second equation the same but in the first row to make easier the calculations then:

2x + 3y = 7400

(x + y ) (-2) = 3000 (-2) solve the multiplications

2x + 3y = 7400

-2x - 2y = -6000 solve the operations

0 + 1y = 1400 clear y

$y = \frac{1400}{1}$ solve the division

y = 1400

For calculate x, replace the y value in the first equation and solve it

x + 1400 = 3000

x = 3000 - 1400

x = 1600

- Answer

The concession stand has sold 1600 sodas and 1400 hotdogs

6 0

3 years ago

Factor by using the difference of two cubes

Nikolay [14]

Answer:

Step-by-step explanation:

a) a^3-64b^3

=(a)^3-(4b)^3

=(a-4b)(a^2+4ab+16b^2)

b) 3x^3-81y^3z^6

=3(x^3-27y^3z^6)

=3{(x)^3-(3yz^2)^3}

=3(x-3yz^2)(x^2+3xyz^2+9y^2z^4)

c)16a^3b^3-54c^3d^3

=2(8a^3b^3-27c^3d^3)

=2{(2ab)^3-(3cd)^3

=2(2ab-3cd)(4a^2b^2+6abcd+9c^2d^2)

hope u got!!

6 0

3 years ago

7. Change the fraction 13/20 to a decimal.

Contact [7]

Answer:

divide it using a calculator

5 0

3 years ago

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