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castortr0y [4]
2 years ago
13

Solve for x and show all work thanks:)

Mathematics
1 answer:
VladimirAG [237]2 years ago
3 0

Answer:

x = -6

Step-by-step explanation:

The triangle in the picture is an isoceles triangle in which the measure of top vertex angle is given and one of the base angles is also given.

According to angle sum property of triangle , sum of measure of all the angles of traingle is 180°. Also, in isosceles triangle , the base angles are always equal to each other .

So,

34 + (x + 79) + (x + 79) = 180

=  > 2x + 158 + 34 = 180

=  > 2x +192 = 180

=  > 2x = 18 0 - 192 =  - 12

=  > x = \frac{12}{ - 2}  =  - 6

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HELP PLEASE 80 POINTS
alexgriva [62]

Answer:

  • x = 15/p
  • x = -3

Step-by-step explanation:

<h3>Given</h3>
  • 4(px + 1)=64
<h3>Find</h3>
  • Solve for x
  • Find x when p = -5
<h3>Solution</h3>
  • 4(px + 1) = 64
  • 4(px + 1)/4 = 64/4
  • px + 1 = 16
  • px = 15
  • x = 15/p

<u>When p = -5, substitute p:</u>

  • x = 15/p
  • x = 15/(-5) = -3
4 0
2 years ago
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Plz answer these questions
Oxana [17]

Answer:

median 1B: 310

Step-by-step explanation:

4 0
2 years ago
For z = –2 + 2i, which graph represents z and –2z?
iVinArrow [24]

Answer:

Graph B

Step-by-step explanation:

6 0
3 years ago
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Which function has a simplified base of 4RootIndex 3 StartRoot 4 EndRoot? f(x) = 2(RootIndex 3 StartRoot 16 EndRoot) Superscript
PIT_PIT [208]

Answer:

  f(x)=4\sqrt[3]{16}^{2x}

Step-by-step explanation:

We believe you're wanting to find a function with an equivalent base of ...

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The functions you're looking at seem to be ...

  f(x)=2\sqrt[3]{16}^x\approx 2\cdot2.5198^x\\\\f(x)=2\sqrt[3]{64}^x=2\cdot 4^x\\\\f(x)=4\sqrt[3]{16}^{2x}\approx 4\cdot 6.3496^x\ \leftarrow\text{ this one}\\\\f(x)=4\sqrt[3]{64}^{2x}=4\cdot 16^x

The third choice seems to be the one you're looking for.

9 0
3 years ago
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Place the numbers 0 to 8, inclusive, in the magic square so that the sum of the numbers in each row, column, and diagonal is the
ehidna [41]

Answer: See attached table

Step-by-step explanation:

\begin{table}[]\begin{tabular}{lllll} &  &  &  &  \\ &  &  &  &  \\ &  &  &  &  \\ &  &  &  & \end{tabular}\end{table}+---+---+---+

| 1 | 8 | 2 |

+---+---+---+

| 6 | 4 | 2 |

+---+---+---+

| 5 | 0 | 7 |

+---+---+---+

<u>Proofs:</u>
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Second row: 8+4+0 = 12

Third row: 2+2+7 = 12

First column: 1+8+2 = 12

Second column: 6+4+2 = 12

Third column: 5+0+7 = 12

Diagonal starting from top left to bottom right: 1+4+7 = 12

Diagonal staring from top right to bottom left: 2+4+5 = 12

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