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Sauron [17]
3 years ago
10

Does 3 and the square roots of 8 and 17 form a right triangle

Mathematics
1 answer:
Gala2k [10]3 years ago
4 0
If it’s is a right triangle then
A^2 + B^2 = C^2
3^2 + (square root of 8)^2 = 17^2

I don’t have a calculator but type that in and if it doesn’t equal 17^2 than the answer is no it doesn’t make a right triangle
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SOLVE THIS PROBLEM, PLEASE! :(
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Answer:

1st Blank: 5

2nd Blank: 3

3rd Blank: -8

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5th Blank: 12

Step-by-step explanation:

15x+35y=-100

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44       44

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Let X denote the lifetime of a machine component with an exponential distribution. The mean time for the component failure is 25
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Answer:

15.8 % ???

at z = 1 p=.8413

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Step-by-step explanation:

7 0
3 years ago
Harold wants to get at a grade of 70 to 75 in his math class. His grade will be the average
ratelena [41]

Answer:

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3 years ago
∠A=24∘and ∠B=24∘ What term can be used to describe these two angles?
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3 years ago
Read 2 more answers
The American Water Works Association reports that the per capita water use in a single-family home is 67 gallons per day. Legacy
inessss [21]

Answer:

We conclude that the null hypothesis is rejected which means residents of Legacy Ranch use less water on average.

Step-by-step explanation:

We are given that the American Water Works Association reports that the per capita water use in a single-family home is 67 gallons per day.

Twenty-three owners responded, and the sample mean water use per day was 63 gallons with a standard deviation of 8.1 gallons per day.

<u><em>Let </em></u>\mu<u><em> = average water usage by residents of Legacy Ranch.</em></u>

So, Null Hypothesis, H_0 : \mu \geq 67 gallons     {means that the residents of Legacy Ranch uses more or equal to 67 gallons water on average}

Alternate Hypothesis, H_A : \mu < 67 gallons    {means that the residents of Legacy Ranch use less water on average}

The test statistics that will be used here is <u>One-sample t test statistics</u> as we don't know about population standard deviation;

                                 T.S.  = \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean water use per day = 63 gallons

             s = sample standard deviation = 8.1 gallons

             n = sample of responded = 23

So, <u><em>test statistics</em></u>  =  \frac{63-67}{\frac{8.1}{\sqrt{23} } }  ~ t_2_2

                               =  -2.368

The value of the test statistics is -2.368.

<em>Now at 0.025 significance level, the </em><u><em>t table gives critical value of -2.074 at 22 degree of freedom for left-tailed test</em></u><em>. Since our test statistics is less than the critical values of t as -2.368 < -2.074, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to </em><u><em>which we reject our null hypothesis</em></u><em>.</em>

Therefore, we conclude that the residents of Legacy Ranch use less water on average.

8 0
3 years ago
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