The answer is A. To understand that, you need to put it in order by the x's and the y's to get x^2-6x + y^2-16y = -48. Now complete the square on both the x and the y terms to get (x^2-6x+9) +(y^2-16y+64) = -48+9+64. Rewriting that in vertex form on the left and doing the math on the right gives you
(x-3)^2 + (y-8)^2 = 25, which shows you a center of (3,8) and a radius of 5.
Answer:

Step-by-step explanation:
Given
y = 3x + 1
Required
Equation of line that passes through (12,-6) and is perpendicular to y = 3x + 1
First, the slope of the line has to be calculated;
Th slope of a line is the coefficient of x in its linear equation;
This implies that the slope of y = 3x + 1 is 3
Having calculated the slope of the first line;
The relationship between both lines are perpendicularity; this implies that 
Where m_1 = 3 and m_2 is the slope of the secodnd line
becomes

Divide both sides by 3


The equation of the line can be calculated using the folloing formula

Where
and 
The equation becomes


Cross multiply


Collect like terms



Answer:
-15804
Step-by-step explanation:
Answer:
Your answer is :
B. 6a^2 + 3ab
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Step-by-step explanation: