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Gennadij [26K]
3 years ago
5

Why was the term personal computer created?

Computers and Technology
1 answer:
tresset_1 [31]3 years ago
3 0
It was created to show the difference between computers that were owned by companies (at one point they were so large and so expensive that only big groups could afford and store them), and the era when computers became small enough for individuals to be able to fit them in their own homes, and also afford them. The era of the Personal Computer (PC) was a huge changing point in history because it brought a lot of power and connectivity into people's homes that hadn't been available before.
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Brian gathers data from his classmates about the computers they own such as the type of operating system, the amount of memory,
Stells [14]

Incomplete question. The Options read;

A. The year purchased

B. Brian's classmates

C. The amount of memory

D. The type of operating system

Answer:

<u>B. Brian's classmates</u>

Explanation:

<em>Remember,</em> the question is concerned about <em>"the individuals"</em> in the data set, <u>so the year they purchased their computer, neither is the amount of memory of the computer and the type of operating system can be classified as individuals in the data set.</u>

Hence, we can correctly say, only Brian's classmates are the individuals in this data set.

4 0
3 years ago
Please answer my question y'all!
katrin [286]

Answer:

Explanation:1000 mp3s

6 0
3 years ago
Read 2 more answers
What is the best approach to testing a website? visit all pages to verify that they load visit every page and verify all links v
shusha [124]

Answer:

B, visit every page and verify all links

Explanation:

6 0
2 years ago
Create the following SQL Server queries that access the Northwind database. Place them in a zip file and place the zip file in t
neonofarm [45]

Answer:

1. SELECT e.EmployeeID, e.FirstName, e.LastName, COUNT(*) as OrderByEmployee FROM Employees e

JOIN Orders o

ON e.EmployeeID = o.EmployeeID

WHERE YEAR(o.OrderDate) = '1996'

GROUP BY e.EmployeeID,e.FirstName,e.LastName

ORDER BY OrderByEmployee DESC

2. SELECT o.OrderID,c.CustomerID, o.OrderDate,SUM((od.Quantity)*

od.UnitPrice - od.Discount)) as TotalCost FROM Orders o

JOIN [Order Details] od

ON od.OrderID = o.OrderID

JOIN Customers c

ON o.CustomerID = c.CustomerID

WHERE (MONTH(OrderDate)= 7 OR MONTH(OrderDate) = 8) and

YEAR(OrderDate) = 1996

GROUP BY o.OrderID,c.CustomerID, o.OrderDate

ORDER BY TotalCost DESC

3. SELECT c.CustomerID, c.CompanyName, c.City, COUNT(o.OrderID) as TotalOrder, SUM(od.Quantity* od.UnitPrice) as TotalOrderAmount FROM Customers c

JOIN Orders o

ON o.CustomerID = c.CustomerID

JOIN [Order Details] od

ON od.OrderID = o.OrderID

WHERE c.Country = 'USA'

GROUP BY c.CustomerID, c.CompanyName, c.City

ORDER BY c.City, c.CustomerID

4. SELECT c.CustomerID, c.CompanyName, c.City, COUNT(o.OrderID) as TotalOrder, SUM(od.Quantity* od.UnitPrice) as TotalOrderAmount FROM Customers c

JOIN Orders o

ON o.CustomerID = c.CustomerID

JOIN [Order Details] od

ON od.OrderID = o.OrderID

WHERE c.Country = 'USA'

GROUP BY c.CustomerID, c.CompanyName, c.City

HAVING COUNT(o.OrderID) > 3

ORDER BY c.City, c.CustomerID

5. SELECT p.ProductID, p.ProductName, s.ContactName as SupplierName, MAX(o.OrderDate) as LastOrderDateOfProduct FROM Products p

JOIN Categories c

ON c.CategoryID = p.CategoryID

JOIN Suppliers s

ON s.SupplierID = p.SupplierID

JOIN [Order Details] od

ON od.ProductID = p.ProductID

JOIN Orders o

ON o.OrderID = od.OrderID

where c.CategoryName = 'Grains/Cereals'

GROUP BY p.ProductID, p.ProductName, s.ContactName

ORDER BY SupplierName, p.ProductName

6. SELECT p.ProductID, p.ProductName, Count(DISTINCT c.CustomerID ) as OrderByThisManyDistinctCustomer

FROM Products p

JOIN [Order Details] od

ON od.ProductID = p.ProductID

JOIN Orders o

ON o.OrderID = od.OrderID

JOIN Customers c

ON c.CustomerID = o.CustomerID

where YEAR(o.OrderDate) = 1996

GROUP BY p.ProductID, p.ProductName

Explanation:

The six query statements returns data from the SQL server Northwind database. Note that all the return data are grouped together, this is done with the 'GROUP BY' Sql clause.

8 0
3 years ago
clinical outcomes and survival differences between primary, secondary and concomitants carcinoma in situ of urinary bladder trea
8_murik_8 [283]

The summary of the research - clinical outcomes and survival differences between primary, secondary and concomitants carcinoma in situ of urinary bladder treated with BCG Immunotherapy is given below.

<h3>What is the summary of the above research?</h3>

Urinary bladder carcinoma in situ (CIS) is a flat, high-grade, and aggressive form of urothelial cancer with a high likelihood of development to muscle-invasive illness and metastatic dissemination.

The study's goal was to compare the clinical histories and survival rates of primary, secondary, and concurrent CIS of the bladder.

Learn more about Immunotherapy at brainly.com/question/14493516

#SPJ1

6 0
1 year ago
Read 2 more answers
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