Answer:
Follows are the solution to this question:
Explanation:
In point a:
Let,
The address of 1-bit memory to add in 2 location:
The address of 2-bit memory to add in 4 location:
similarly,
Complete 'n'-bit memory address' location number is = Here, 12-bit memory address, i.e. n = 12, hence the numeral. of the addressable locations of the memory:
In point b:
So,
The memory position for '' could be 'n' m bits'
It can use bits to address the memory location of 21.
That is to say, the 2-mega-location memory needs '21' bits.
Memory Length = 21 bit Address
In point c:
element array addresses are given by:
1 term is 4 bytes in 'MIPS,' that is:
In point d:
When MIPS is 1 word which equals to 32 bit :
In Unicode, its value is = 2 byte
In ASCII code its value is = 1 byte
both sizes are < 4 byte
Calculating address: