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gtnhenbr [62]
2 years ago
5

A desktop computer is a type of mobile device. a. true b. false

Computers and Technology
1 answer:
Charra [1.4K]2 years ago
4 0
Answer:B.false
Answer B
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Two machines can finish a job in StartFraction 20 Over 9 EndFraction hours. Working​ alone, one machine would take one hour long
Alborosie

<em><u>Answer</u></em>

5 hours

<em><u>Explanation</u></em>

The two working together can finish a job in

\frac{20}{9}  \: hours

Also, working alone, one machine would take one hour longer than the other to complete the same job.

Let the slower machine working alone take x hours. Then the faster machine takes x-1 hours to complete the same task working alone.

Their combined rate in terms of x is

\frac{1}{x}    +  \frac{1}{x - 1}

This should be equal to 20/9 hours.

\frac{1}{x}  +  \frac{1}{x - 1}  =  \frac{9}{20}

Multiply through by;

20x(x - 1) \times \frac{1}{x}  +20x(x - 1) \times   \frac{1}{x - 1}  =  20x(x - 1) \times \frac{9}{0}

20(x - 1)  +20x = 9x(x - 1)

20x - 20+20x = 9{x}^{2}  - 9x

9{x}^{2}  - 9x - 20x - 20x + 20= 0

9{x}^{2}  - 49x  + 20= 0

Factor to get:

(9x - 4)(x - 5) = 0

x =  \frac{4}{9}  \: or \: x = 5

It is not feasible for the slower machine to complete the work alone in 4/9 hours if the two will finish in 20/9 hours.

Therefore the slower finish in 5 hours.

8 0
3 years ago
Dyn is a cloud-based internet performance management company that provides DNS services for internet websites. It was attacked w
notsponge [240]

Answer: ......

Explanation: yes

8 0
3 years ago
Does anyone know about ICT? i need help ASAP
Lina20 [59]
ICT means, Information and Communication Technologies

ICT is a borders term for information technology which refers to all communication technologies including the Internet wireless networks, cell phones, computers, software, middleware, video-conferencing, social networking and other media applications and services
4 0
3 years ago
Output a table that show the cube of the numbers 1-15<br> (C++)
Rainbow [258]

Answer:

The c++ program to display cube of numbers from 1 to 15 is given below.

#include <iostream>

using namespace std;

int main() {    

   // variables declared and initialized  

   int num = 15, k, cube;    

   cout << " Cubes of numbers from 1 to 15 are shown below " << endl;    

   for( k = 1; k <= num; k++ )

   {

       // cube is calculated for each value of k and displayed

       cube = k * k * k ;

       cout << " \t " << cube << endl;

   }

return 0;

}

 

OUTPUT

Cubes of numbers from 1 to 15 are shown below  

  1

  8

  27

  64

  125

  216

  343

  512

  729

  1000

  1331

  1728

  2197

  2744

  3375

Explanation:

The variables are declared and initialized for loop, cube and for condition in the loop – k, cube, num respectively.

Inside for loop which executes over k, beginning from 1 to 15, cube of each value of k is calculated and displayed. The loop executes 15 times. Hence, cube for numbers from 1 to 15 is displayed after it is calculated.

   for( k = 1; k <= num; k++ )

   {

      cube = k * k * k ;

       cout << " \t " << cube << endl;

   }

In the first execution of the loop, k is initialized to 1 and variable cube contains cube of 1. Hence, 1 is displayed on the screen.

In the second execution, k is incremented by 1 and holds the value 2. The variable cube contains cube of 2, which is calculated, and 8 gets displayed on the screen.

After each execution of the loop, value of k is incremented.

After 15 executions, value of k is incremented by 1 and k holds the value 16. This new value is greater than num. Hence, the loop terminates.

3 0
3 years ago
The CPU's control unit retrieves the next instruction in a sequence of program instructions from main memory in the ______ stage
Varvara68 [4.7K]

Answer:

A. Fetch.

Explanation:

The fetch-decode-execute process of simply the fetch-execute process of the CPU are stages the CPU follow to process information and the switch state or shutdown.

The stages of this process is implied in its name, that is, the stages are fetch, decide and execute.

The fetch stage retrieves the next instruction from the memory.

The decode stage converts the clear text instruction set to electronic signals and transfer it to the appropriate registers.

The execute stage is the action carried out in the arithmetic logic unit.

5 0
3 years ago
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