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IrinaK [193]
2 years ago
6

A jar contains 133. A bigger jar contains 1 2/7 times as many pennies.what is the value of the pennies in the bigger jar

Mathematics
1 answer:
adoni [48]2 years ago
4 0
A jar contains 133 pennies....a bigger jar contains 1 2/7 times as much


so the bigger jar contains :
1 2/7 * 133
9/7 * 133 =
1197/7 =
171 pennies <===
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An object with a mass of 3.2 kg has a force of 7.3 newtons applied to it. What is the resulting acceleration of the object?
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Answer : 10.5

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2 years ago
In triangle ABC, what is m angle C
Degger [83]

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83.5 degrees

Step-by-step explanation:

first, find x:

x+5x-13+4x=180

10x=193

x=19.3

Then, substitute that value for c:

5*19.3-13

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2 years ago
Minerva starts a savings account with $50. The interest on the account balance is compounded annually. The graph below shows the
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We can set up this equation using this formula:

a = p(1 + r/n)^nt

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We'd set it up like this:

a = 50(1 + ?/1)^1(12)

Because we're missing the amount of interest, it would be impossible to tell what the amount would be after 12 years.


6 0
2 years ago
Which fractions are equievalent? a.20/5 b.-20/5 c.20/-5 d. -20/-5 e.- 20/5
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Step-by-step explanation:


6 0
3 years ago
QUESTION 1
Kitty [74]

It's difficult to make out what the force and displacement vectors are supposed to be, so I'll generalize.

Let <em>θ</em> be the angle between the force vector <em>F</em> and the displacement vector <em>r</em>. The work <em>W</em> done by <em>F</em> in the direction of <em>r</em> is

<em>W</em> = <em>F</em> • <em>r</em> cos(<em>θ</em>)

The cosine of the angle between the vectors can be obtained from the dot product identity,

<em>a</em> • <em>b</em> = ||<em>a</em>|| ||<em>b</em>|| cos(<em>θ</em>)   ==>   cos(<em>θ</em>) = (<em>a</em> • <em>b</em>) / (||<em>a</em>|| ||<em>b</em>||)

so that

<em>W</em> = (<em>F</em> • <em>r</em>)² / (||<em>F</em>|| ||<em>r</em>||)

For instance, if <em>F</em> = 3<em>i</em> + <em>j</em> + <em>k</em> and <em>r</em> = 7<em>i</em> - 7<em>j</em> - <em>k</em> (which is my closest guess to the given vectors' components), then the work done by <em>F</em> along <em>r</em> is

<em>W</em> = ((3<em>i</em> + <em>j</em> + <em>k</em>) • (7<em>i</em> - 7<em>j</em> - <em>k</em>))² / (√(3² + 1² + 1²) √(7² + (-7)² + (-1)²))

==>   <em>W</em> ≈ 5.12 J

(assuming <em>F</em> and <em>r</em> are measured in Newtons (N) and meters (m), respectively).

3 0
3 years ago
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