(w-2)^2 = 63
FOIL left hand side:
(w-2)^2 = w^2 - 4w + 4
So,
w^2 - 4w + 4 = 63
w^2 - 4w - 59 = 0
Then use quadratic equation to get values of w = 2 + 3*root(7) and w = 2 - 3*root(7).
±
3
√
7
Answer:
30.2609
Step-by-step explanation:
-4.8402-(-35.1011)
-4.8402+35.1011
30.2609
Please mark me as Brainliest if you're satisfied with the answer.
Https://youtu.be/dQw4w9WgXcQ that helps too
Step-by-step explanation:
Lets first find the remainder when p(x) is divided by x-2
p(2)=2(2)³+b(2)²+3(2)-5
p(2)=16+4b+6-5
p(2)=4b+17
Now let's find the remainder when q(x) is divided by x-2
q(2)=(2)³+(2)²-4(2)-b
q(2)=8+4-8-b
q(2)=4-b
Now let's equate both of them
4b+17=4-b
4b+b=4-17
5b=-13
b=-13/5 as required
Answer: EGF
Step-by-step explanation:
