9.3 due to the fact that 93/10 is 9.3 hopefully that helps
Answer:
(a)Food-12%
9b)Transportation-17%
Step-by-step explanation:
In the Year 2000
- Average Household Income (before taxes)=$44,649
- Amount Spent on Food =$5,158
- Amount Spent on Transportation=$7,417
Therefore:
(a)Percentage of the average household income in 2000 was spent on food
(b)Percentage of the average household income in 2000 was spent on transportation
Answer:
0.7361
Step-by-step explanation:
In this question we have
number to be 10
Then we have a probability of 10% = 0.10
We have q = 1-p
= 1-0.10 = 0.90
Then the probability of not more than 1 being defective:
P(x=0) + p(x= 1)
(10C0 x 0.1⁰ x 0.9^10-0)+(10C1 x 0.1¹ x 0.9^10-1)
= 1 x1 x0.3487 + 10 x 0.1 x 0.3874
= 0.3487 + 0.3874
= 0.7361
This is the the required probability and this answers the question.
probability = 10 percent = 0.1
q= 1- 10percent = 90% = 0.9
n = 4
To get the required probabiltiy for this question is
P(not greater than one is defective )=P(x=0)+P(x=1)
= 4C0x(0.1)⁰x(0.9)⁴+4C1x(0.1)¹x(0.9)³
= 0.9477
The required probability is 0.9477
Answer:
Step-by-step explanation:
Siamone has $65.32 + DAN
Dan has CARLY - $37.50
CARLY = $127.75
Plug Carly into Dan's equation...
$127.75 - $37.50 = $90.20
DAN = $90.20
Plug Dan into Siamone's equation
$65.32 + $90.20 = $155.57
