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3 years ago

Which line has a slope of zero? (Hint:Think Hoy VUX/slpe man)

Mathematics

2 answers:

maria [59]3 years ago

4 0

Answer:

The answer will be listed below.

Step-by-step explanation:

I don't see any options, but to find a line with a slope of zero, the line must be straight either vertically or horizontally.

nikitadnepr [17]3 years ago

3 0

A vertical line has a slope of zero.

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Why does -2^6 equal -64 but -2 x -2 x -2 x -2 x -2 x -2 equal 64?

user100 [1]

Answer:

Step-by-step explanation:

-2⁶ = -(2⁶) = -(64) = -64

(-2)×(-2)×(-2)×(-2)×(-2)×(-2) = (-2)⁶ = (-1⋅2)⁶ = (-1)⁶⋅2⁶ = 1⁶⋅2⁶ = 64

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2 years ago

Given a circle with a diameter of 8, what is the circumference?

sveticcg [70]

You multiply 8 by pi = 25.12

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3 years ago

What is the slope of the line y = 1?

Oxana [17]

Answer:

Can't help on slopes

Step-by-step explanation:

other numbers or graphs have to be included

7 0

3 years ago

Read 2 more answers

ASAP! GIVING BRAINLIEST! Please read the question THEN answer correctly! No guessing.

Snezhnost [94]

Answer:

B yes, because every x value corresponds to exactly one y value

Step-by-step explanation:

A function means that each input goes to a different output

Each input goes to only 1 y value

4 0

3 years ago

Read 2 more answers

The doubling period of a bacterial population is 20 20 minutes. At time t = 100 t=100 minutes, the bacterial population was 9000

Nuetrik [128]

Answer:

The initial population was 2810

The bacterial population after 5 hours will be 92335548

Step-by-step explanation:

The bacterial population growth formula is:

$P = P_0 \times e^{rt}$

where P is the population after time t, $P_0$ is the starting population, i.e. when t = 0, r is the rate of growth in % and t is time in hours

Data: The doubling period of a bacterial population is 20 minutes (1/3 hour). Replacing this information in the formula we get:

$2 P_0 = P_0 \times e^{r 1/3}$

$2 = e^{r \; 1/3}$

$ln 2 = r \; 1/3$

$ln 2 \times 3 = r$

$2.08 \% = r$

Data: At time t = 100 minutes (5/3 hours), the bacterial population was 90000. Replacing this information in the formula we get:

$90000 = P_0 \times e^{2.08 \; 5/3}$

$\frac{9000}{e^{2.08 \; 5/3}} = P_0$

$2810 = P_0$

Data: the initial population got above and t = 5 hours. Replacing this information in the formula we get:

$P = 2810 \times e^{2.08 \; 5}$

$P = 92335548$

3 0

3 years ago