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mrs_skeptik [129]
3 years ago
5

Mount mckinley in alaska is 20,320 feet above sea level. Mauna kea in hawaii is 13,796 feet above sea level. How many more feet

above sea level is mount mckinley than mauna kea?
Mathematics
1 answer:
strojnjashka [21]3 years ago
4 0

To solve this problem you must apply the proccedure shown below:

1. You have the following information given in the problem above:

- Mount Mckinley is 20,320 feet above sea level.

- Mauna kea is 13,796 feet above sea level.

2. Then, you only need to substract both quantities to solve the exercise, as following:

20,320ft-13,796ft=6,524ft

Therefore, as you can see, the answer is: 6,524 feet.

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: Use The TI Calculator To Answer The Question. Find The Probability That A Z-score Will Be Between 0.7 And 1.4. A) 0.242 O B) 0
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Answer:

P(0.7

And we can find this probability with the following difference:

P(0.7

We can use the following commands on the ti 84

2nd>VARS>DISTR

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normalcdf(0.7,1.4,0,1)

The other possible code would be:

normalcdf(-1000,1,4,0,1)-normalcdf(-1000,0.7,0,1)

And we got:

P(0.7

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

For this case we want to find this probability:

P(0.7

And we can find this probability with the following difference:

P(0.7

We can use the following commands on the ti 84

2nd>VARS>DISTR

And then we look for normalcdf and we input this:

normalcdf(0.7,1.4,0,1)

The other possible code would be:

normalcdf(-1000,1,4,0,1)-normalcdf(-1000,0.7,0,1)

And we got:

P(0.7

3 0
3 years ago
Read 2 more answers
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