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noname [10]
3 years ago
8

Which of the following is the smallest volume?

Mathematics
2 answers:
Phoenix [80]3 years ago
7 0
250 cm3 so it's b your welcome
Lyrx [107]3 years ago
5 0
B. 250 cm3 hope this helps 
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If the typical balance on Lucy's credit card is $650 and the interest rate (APR) on her credit card is 18%, how much in interest
mafiozo [28]

General Idea:

Amount \; Charged \; in \; a \; Month \; = \; Monthly \; Interest \; Rate \; \times Typical \; Creditcard\; Balance\\ \\

Amount \; Charged \; in\; a\; month =\frac{18\%}{12} \times 650 \; = 0.015\times650=9.75

Conclusion:

Amount of interest that Lucy to be charged in a typical month is <u>$9.75</u>

7 0
3 years ago
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I don’t understand this at all
Romashka [77]

Answer:

a) the midpoint is (1.5, 2.5)

b) the line is y = -(7/3)*x + 6.

Step-by-step explanation:

a)

Suppose we have two values, A and B, the mid-value between A and B is:

(A + B)/2

Now, if we have a segment with endpoints (a, b) and (c, d), the midpoint will be in the mid-value of the x-components and the mid-value of the y-components, this means that the midpoint is:

( (c + a)/2, (b + d)/2)

a) Then if the endpoints of the segment are (-2, 1) and (5, 4), the midpoint of this segment will be:

( (-2 + 5)/2, (1 + 4)/2) = (3/2, 5/2) = (1.5, 2,5)

The midpoint of the segment is (1.5, 2.5)

b)

Now we want to find the equation of a perpendicular line to our segment, that passes through the point (1.5, 2.5).

First, if we have a line:

y = a*x + b

A perpendicular line to this one will have a slope equal to -(1/a)

So the first thing we need to do is find the slope of the graphed segment.

We know that for a line that passes through the points (a, b) and (c, d) the slope is:

slope = (c - a)/(d - b)

Then the slope of the segment is:

slope = (4 - 1)/(5 - (-2)) = 3/7

Then the slope of the perpendicular line will be:

s = -(7/3)

Then the perpendicular line will be something like:

y = -(7/3)*x + d

Now we want this line to pass through the point (1.5, 2.5), then we can replace the values of this point in the above equation, and solve for d.

2.5 = -(7/3)*1.5 + d

2.5 + (7/3)*1.5 = d = 6

Then the line is:

y = -(7/3)*x + 6

7 0
3 years ago
How much fudge will each person get if 7 people share one half of a pound of fudge equally? Ow much fudge will each person get i
Andrews [41]

Answer:

B

Step-by-step explanation:

one half lb divided by 7 people will equal one fourteenth

8 0
3 years ago
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Andrew borrows $79,500 for 5 months on 6.30% interest rate in his saving account. calculate the simple interest
alukav5142 [94]
Equation i= p time r time T 79500 time .0630 time .42 Equal 21,035.7 simple interest Dos Doctor pepper on the interest, going back two time on the left which would become .0630 5 divide month of 12 which is .41666 Round to the nearest tenth which is .42
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Yea I can do tomorrow it would take me to get the money back to you
Tems11 [23]

Given, the equation that represents the height of an object:

y(t)=100t-16t^2

First, we will find the velocity of the object which is the first derivative of the height using the method of the limits

\frac{dy}{dt}=\lim_{h\to a}\frac{y(3+h)-y(3)}{(3+h)-(3)}

We will find the value of the function y(t) when t = 3, and when t = 3+h

\begin{gathered} y(3+h)=100(3+h)-16(3+h)^2 \\ y(3+h)=300+300h-16(9+6h+h^2) \\ y(3+h)=300+300h-144-96h-16h^2 \\ y(3+h)=156+4h-16h^2 \\ y(3)=100(3)-16(3)^2=156 \end{gathered}

Substitute y(3+h) and y(3) into the expression of the limit

\begin{gathered} \frac{dy}{dt}|_{t=3}=\lim_{h\to a}\frac{156+4h-16h^2-156}{3+h-3}=\lim_{h\to a}\frac{4h-16h^2}{h} \\  \\ \frac{dy}{dt}|_{t=3}=\lim_{h\to a}(4-16h) \end{gathered}

Where a = 0

d) compute the instantaneous velocity at t = 3

\frac{dy}{dt}|_{t=3}=100-16*2*3=4

So, the answer will be:

\begin{gathered} \frac{dy}{dt}|_{t=3}=\lim_{h\to a}(4-16h) \\ a=0 \\  \\ \frac{dy}{dt}|_{t=3}=4\text{  ft/sec} \end{gathered}

5 0
2 years ago
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