Answer: at the values where cos(x) = 0Justification:1) tan(x) = sin(x) / cos(x).
2) functions have vertical asymptotes at x = a if Limit of the function x approaches a is + or - infinity.
3) the limit of tan(x) approaches +/- infinity where cos(x) approaches 0.
Therefore, the grpah of y = tan(x) has asymptotes where cos(x) = 0.
You can see the asympotes at x = +/- π/2 on the attached graph. Remember that cos(x) approaches 0 when x approaches +/- (n+1) π/2, for any n ∈ N, so there are infinite asymptotes.
Answer:
Y= - 3/x+2/3
Step-by-step explanation:
Answer: No, the money won't be enough to buy the car
Step-by-step explanation:
you plan on buying yourself a new $20,000 car on graduation day and graduation day is 24 months time. If you invest $300 a month for the next 24 months.
The principal amount, p = 300
He is earning 4% a month, it means that it was compounded once in four months. This also means that it was compounded quarterly. So
n = 4
The rate at which the principal was compounded is 4%. So
r = 4/100 = 0.04
It was compounded for a total of 24 months. This is equivalent to 2 years. So
n = 2
The formula for compound interest is
A = P(1+r/n)^nt
A = total amount that would be compounded at the end of n years.
A = 300(1 + (0.04/4)/4)^4×2
A = 300(1 + 0.01)^8
A = 300(1.01)^8
A = $324.857
The total amount at the end of 24 months is below the cost of the car which is $20000. So he won't have enough money to buy the car
Answer:
since -3.73 is less than 1.645, we reject H₀.
Therefore this indicate that the proposed warranty should be modified
Step-by-step explanation:
Given that the data in the question;
p" = 13/20 = 0.65
Now the test hypothesis;
H₀ : p = 0.9
Hₐ : p < 0.9
Now lets determine the test statistic;
Z = (p" - p ) / √[p×(1-p)/n]
= (0.65 - 0.9) /√[0.9 × (1 - 0.9) / 20]
= -0.25 / √[0.9 × 0.1 / 20 ]
= -0.25 / √0.0045
= -0.25 / 0.067
= - 3.73
Now given that a = 0.05,
the critical value is Z(0.05) = 1.645 (form standard normal table)
Now since -3.73 is less than 1.645, we reject H₀.
Therefore this indicate that the proposed warranty should be modified
Answer:
I think it is 730
Step-by-step explanation:
I hope this helped o(〃＾▽＾〃)o
