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alexandr1967 [171]
3 years ago
14

Allison buys equipment and pays cash of $50,000, signs a note of $10,000 and assumes a liability on the property for $3,000. In

addition. Allison pays an installation coat of $500 and a delivery coat of $800. Allison's basis in the asset is A) $63, 500. B) $63,000. C) $64, 300. D) $60,000.
Business
1 answer:
slava [35]3 years ago
3 0

Answer:

The answer is C) $64, 300.

Explanation:

basis in a business asset is basically the cost of that asset.

Allison's basis in the asset= $50,000+ $10,000+ $3,000+ $800+ $500 =  $64,300.

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You are considering taking out one of two loans. Loan R has a principal of $17,550, an interest rate of 5. 32% (compounded month
Evgesh-ka [11]

The difference between the monthly payment of R and S is equal to $48.53 by following the compound interest formula. Thus, Loan R's monthly loan amount is greater than Loan S.

<h3>What is a Compound interest loan?</h3>

Combined interest (or compound interest) is the loan interest or deposit calculated based on both the original interest and accrued interest from earlier periods.

\rm\,For\,R\\\\P = \$\,17,550\\r\,= 5.32\%\\Time\,= n= 7\,years\\Amount\,paid= [P(1+\dfrac{r}{100\times12})^{n\times12} ]\\=[ 17,550 (1+\dfrac{5.32}{100\times12})^{7\times12} ]\\= [ 17,550 (\dfrac{12.0532}{12})^{84} ]\\\\=  [ 17,550 (1.00443^{84} ]\\\\= \$ 25,440.48\\\\Total\,monthly\,payment = \rm\,\dfrac{25,440.48}{84}\\\\= \$\, $302.86\\\\

\rm\,For\,S =\\\\P=\,\$ 15,925\\r\,= 6.07\%\\T=n= 9\,years\\\\Amount\,paid\,= [P(1+\dfrac{r}{100\times12})^{n\times12} ]\\\\\= [15,925(1+\dfrac{0.0607}{12})^{9\times12} ]\\\\\\= [15,925(1+\dfrac{0.0607}{12})^{108} ]\\\\=[15,925(1.7247.84)} ]\\\\\= \$27,467.19\\\\Total\,monthly\,payment =\dfrac{\rm\,\$\,27,469.19}{108}\\\\= \$ 254.326\\\\

The difference between the monthly payment of R and S is equal to $48.53.

Hence, Loan R's monthly payment is greater than the loan's monthly payment by $48.53

To learn more about Compound interest, refer to the link:

brainly.com/question/14331235

5 0
3 years ago
A machine that cost $225,000 has an estimated residual value of $15,000 and an estimated useful life of 15,000 machine hours. Th
algol [13]

Answer:

$57,000

Explanation:

<u><em>Step 1 : Depreciation Rate</em></u>

Depreciation Rate = (Cost - Residual Value) ÷ Estimated Production

therefore,

Depreciation Rate = $14.00 per machine hour

<u><em>Step 2 : Depreciation expenses</em></u>

Depreciation expense = Depreciation Rate x Annual production

therefore

Year 1 = $42,000

Year 2 = $56,000

Year 3 = $70,000

Total    = $168,000

<em><u>Step 3 : Book Value</u></em>

Book Value = Cost - Accumulated Depreciation

                    = $225,000 - $168,000

                    = $57,000

Conclusion :

book value at the end of year 3 is $57,000

8 0
3 years ago
Frankâ Pianki, the manager of an organic yogurt processing plant desires a quality specification with a mean of 18.0 âounces, an
aleksley [76]

Answer: 0.050

Explanation:

Mean = 18

USL = 18.6

LSL = 17.4

SD = 1.25

Cpk = Min{(mean - LSL / 3*sd), (USL - mean / 3*sd)}

= Min{ ( 18 - 17.4/ 3 * 1.25), (18.6 - 18 / 3 * 1.25)}

= Min { 0.05 0.05)

Cpk = 0.050

8 0
3 years ago
On January 2, 2013, Gant Co. purchased a franchise with a useful life of five years for $60,000 and an annual fee of 1% of franc
inysia [295]

Answer:

$48,000

Explanation:

The computation of the amount that should be reported as the intangible asset franchise is shown below

= Purchase value of franchise - amortization per year

= $60,000 - ($60,000 ÷ 5 years)

= $60,000 - $12,000

= $48,000

hence, the  amount that should be reported as the intangible asset franchise is $48,000

6 0
3 years ago
Hardigree Corporation makes a product that has the following direct labor standards: Standard direct labor-hours 0.3 hours per u
djyliett [7]

Answer:

4,140 U

Explanation:

According to the scenario, calculation of the given data are as follows,

Actual Hours = 2,820 hours

Standard rate = $23 per hour

Standard direct labor hour = 0.3 hours

We can calculate labor efficiency variance by using following formula,

Labor Efficiency Variance = Actual hours standard cost  - Standard cost

Where, Actual hours standard Cost  = Actual hours × Standard rate

= 2,820 × 23

= 64,860

Standard Cost (8,800 units) = Standard hours (8,800 units) × Standard rate

= (8,800 × 0.3) × 23

= 60,720

Hence, by putting the value in the formula, we get

Labor Efficiency Variance  = 64,860 - 60,720

= 4,140 U

8 0
3 years ago
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