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2 years ago

Help me solve this 3-p/(-4) if p =12

1 answer:

5 0

Since ur using 12 as p we solve it now.

3 - 12 over -4 = 6

Move the negative sign to the left (3 - (-12/4)
Simplify 12/4 to 3 ( 3 - (-3)
simplify brackets (3 + 3)
finally the answer is 6

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dlinn [17]

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2 years ago

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2 years ago

3) Solve each equation using the quadratic formula. Show<br> a. x2 – 3x – 10 = 0

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Answer:

Step-by-step explanation:

The quadratic formula of a quadratic equation

$ax^2+bx+c=0\\\\\text{If}\ b^2-4ac>0\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

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$\text{If}\ b^2-4ac$

We have:

$x^2-3x-10=0\to a=1,\ b=-3,\ c=-10\\\\b^2-4ac=(-3)^2-4(1)(-10)=9+40=49>0\\\\x=\dfrac{-(-3)\pm\sqrt{49}}{2(1)}=\dfrac{3\pm7}{2}\\\\x=\dfrac{3-7}{2}=\dfrac{-4}{2}=-2\\or\\x=\dfrac{3+7}{2}=\dfrac{10}{2}=5$

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2 years ago

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Ipatiy [6.2K]

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2 years ago

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2 years ago