Answer:
Step-by-step explanation:
Answer:14
Step-by-step explanation:
Answer:
That looks hard but idk how to answer it
Step-by-step explanation:
Answer:
c = -6
Step-by-step explanation:
To find the value of c to make the line pass through the point K = (2, -3), we just need to use the values of x = 2 and y = -3 in the equation, then we find the value of c.
So, we have that:
y - 1.5*x = c
(-3) - 1.5 * (2) = c
-3 - 3 = c
c = -6
So the value of c is -6
To check if the value is correct, we can use the value x = 2 and see if the value of y is -3:
y - 1.5*x = -6
y - 1.5*2 = -6
y - 3 = -6
y = -6 + 3 = -3
So it's correct.
(a) By the fundamental theorem of calculus,
<em>v(t)</em> = <em>v(0)</em> + ∫₀ᵗ <em>a(u)</em> d<em>u</em>
The particle starts at rest, so <em>v(0)</em> = 0. Computing the integral gives
<em>v(t)</em> = [2/3 <em>u</em> ³ + 2<em>u</em> ²]₀ᵗ = 2/3 <em>t</em> ³ + 2<em>t</em> ²
(b) Use the FTC again, but this time you want the distance, which means you need to integrate the <u>speed</u> of the particle, i.e. the absolute value of <em>v(t)</em>. Fortunately, for <em>t</em> ≥ 0, we have <em>v(t)</em> ≥ 0 and |<em>v(t)</em> | = <em>v(t)</em>, so speed is governed by the same function. Taking the starting point to be the origin, after 8 seconds the particle travels a distance of
∫₀⁸ <em>v(u)</em> d<em>u</em> = ∫₀⁸ (2/3 <em>u</em> ³ + 2<em>u</em> ²) d<em>u</em> = [1/6 <em>u</em> ⁴ + 2/3 <em>u</em> ³]₀⁸ = 1024
