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saveliy_v [14]
3 years ago
9

Dawn has been using two bank accounts to save money for a car. The difference between account 1 and account 2 is $100. If she us

es 3/8 of account 1 and 7/8 of account 2, Dawn will have a down payment of $2,000. Solve the system of equations to find the total amount of money Dawn has in each account. A – B = 100 A + B = 2,000
Mathematics
1 answer:
MakcuM [25]3 years ago
6 0

Answer:

0.25

Step-by-step explanation:

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In a typical week you drive 34.85 km on Monday, 28.23 km on
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63.08 km

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The CEO of a large corporation asks his Human Resource (HR) director to study absenteeism among its executive-level managers at
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Answer:

Following are the answer to this question:

Step-by-step explanation:

Given:

n = 30 is the sample size.  

The mean  \bar X = 7.3 days.  

The standard deviation = 6.2 days.  

df = n-1  

     = 30-1 \\      =29

The importance level is \alpha = 0.10  

The table value is calculated with a function excel 2010:

= tinv (\ probility, \ freedom \ level) \\= tinv (0.10,29) \\ =1.699127\\ =  t_{al(2x-1)}= 1.699127

The method for calculating the trust interval of 90 percent for the true population means is:

Formula:

\bar X - t_{al 2,x-1} \frac{S}{\sqrt{n}} \leq \mu \leq \bar X+ t_{al 2,x-1}   \frac{S}{\sqrt{n}}

=\bar X - t_{0.5, 29} \frac{6.2}{\sqrt{30}} \leq \mu \leq \bar X+ t_{0.5, 29}   \frac{6.2}{\sqrt{30}}\\\\=7.3 -1.699127 \frac{6.2}{\sqrt{30}}\leq \mu \leq7.3 +1.699127 \frac{6.2}{\sqrt{30}}\\\\=7.3 -1.699127 (1.13196)\leq \mu \leq7.3 +1.699127  (1.13196) \\\\=5.37 \leq \mu  \leq 9.22 \\

It can rest assured that the true people needs that middle managers are unavailable from 5,37 to 9,23 during the years.

7 0
3 years ago
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