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agasfer [191]
3 years ago
11

Define a variable and write an expression for the phrase. 8 minus a number

Mathematics
2 answers:
soldier1979 [14.2K]3 years ago
6 0
8-x would be the equassion
Reil [10]3 years ago
5 0
Since it is just an expression the answer is 
8-x
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Need help with math probelm if do 5 stars
slamgirl [31]

Answer:

b) -9.25

Step-by-step explanation:

-1/4 = -0.25

-9 + -0.25 = -9.25

-10, -9.75, -9.5, -9.25, -9, -8.75, -8.5, -8.25, -8, -7.75, -7.5, -7.25, -7

Hope this helps!

4 0
2 years ago
Read 2 more answers
Given f(x)=21x+14, find f(5)
loris [4]

f(5)=21\cdot5+14=105+14=119

6 0
3 years ago
A source of information randomly generates symbols from a four letter alphabet {w, x, y, z }. The probability of each symbol is
koban [17]

The expected length of code for one encoded symbol is

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha\ell_\alpha

where p_\alpha is the probability of picking the letter \alpha, and \ell_\alpha is the length of code needed to encode \alpha. p_\alpha is given to us, and we have

\begin{cases}\ell_w=1\\\ell_x=2\\\ell_y=\ell_z=3\end{cases}

so that we expect a contribution of

\dfrac12+\dfrac24+\dfrac{2\cdot3}8=\dfrac{11}8=1.375

bits to the code per encoded letter. For a string of length n, we would then expect E[L]=1.375n.

By definition of variance, we have

\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2

For a string consisting of one letter, we have

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha{\ell_\alpha}^2=\dfrac12+\dfrac{2^2}4+\dfrac{2\cdot3^2}8=\dfrac{15}4

so that the variance for the length such a string is

\dfrac{15}4-\left(\dfrac{11}8\right)^2=\dfrac{119}{64}\approx1.859

"squared" bits per encoded letter. For a string of length n, we would get \mathrm{Var}[L]=1.859n.

5 0
3 years ago
What is f(x)=x; g(x)=x+3
eduard

Answer:

A

Step-by-step explanation:


3 0
3 years ago
the diagram shows a circle of radius 3cm drawn inside a square.write down the exact value of the following and state whether the
rewona [7]

Answer:

The circumference of the circle

Step-by-step explanation:

5 0
2 years ago
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