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3 years ago

Describe translation needed for the image of the rectangle to have w at point (-5,6)

Mathematics

1 answer:

Alika [10]3 years ago

5 0

We need the image to answer. we wont be able to transform something that we can't see

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Plssss help (the answer choices are the same for all)

Lilit [14]

1) x < 8/3
2) x > -9
3) Infinite Solutions
4) No Solution

Please correct me if I’m wrong. Hope this helps!

3 0

2 years ago

What is the equation of this line

photoshop1234 [79]

Answer:

$y = -\frac{4}{3}x + 4$

Step-by-step explanation:

Use the slope-intercept form to write the equation if the line of the graph given.

$y = mx + b$ , where,

b = y-intercept, which is where the line cuts across the y-axis = 4.

m = slope = $\frac{y_2 - y_1}{x_2 - x_1} = \frac{0 - 4}{3 - 0} = \frac{-4}{3}$

Substitute m = ⁴/3 and b = 4, into the slope-intercept formula to get the equation of the line:

$y = mx + b$

$y = -\frac{4}{3}x + 4$

8 0

2 years ago

8-2b=-2(b=-3;b=0;b=5)

lions [1.4K]

Ekgful4y98pyr89495yt82h9

4 0

2 years ago

Read 2 more answers

hi, i dont undertand number 20 because i was absent in class today and i rerally need help, i will appraciate with the help, and

Mariulka [41]

Given:

The equation is,

$2\log _3x-\log _3(x-2)=2$

Explanation:

Simplify the equation by using logarthimic property.

$\begin{gathered} 2\log _3x-\log _3(x-2)=2 \\ \log _3x^2-\log _3(x-2)=2_{}\text{ \lbrack{}log(a)-log(b) = log(a/b)\rbrack} \\ \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \end{gathered}$

Simplify further.

$\begin{gathered} \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \\ \frac{x^2}{x-2}=3^2 \\ x^2=9(x-2) \\ x^2-9x+18=0 \end{gathered}$

Solve the quadratic equation for x.

$\begin{gathered} x^2-6x-3x+18=0 \\ x(x-6)-3(x-6)=0 \\ (x-6)(x-3)=0 \end{gathered}$

From the above equation (x - 6) = 0 or (x - 3) = 0.

For (x - 6) = 0,

$\begin{gathered} x-6=0 \\ x=6 \end{gathered}$

For (x - 3) = 0,

$\begin{gathered} x-3=0 \\ x=3 \end{gathered}$

The values of x from solving the equations are x = 3 and x = 6.

Substitute the values of x in the equation to check answers are valid or not.

For x = 3,

$\begin{gathered} 2\log _3(3^{})-\log _3(3-2)=2 \\ 2\log _33-\log _31=2 \\ 2\cdot1-0=2 \\ 2=2 \end{gathered}$

Equation satisfy for x = 3. So x = 3 is valid value of x.

For x = 6,

$\begin{gathered} 2\log _36-\log _3(6-2)=2 \\ 2\log _36-\log _34=2 \\ \log _3(6^2)-\log _34=2 \\ \log _3(\frac{36}{4})=2 \\ \log _39=2 \\ \log _3(3^2)=2 \\ 2\log _33=2 \\ 2=2 \end{gathered}$

Equation satifies for x = 6.

Thus values of x for equation are x = 3 and x = 6.

6 0

9 months ago

If you cut a right rectangular prism parallel to its base, apply ink to the cross section, and stamp it on a sheet of paper, whi

kondor19780726 [428]

It would be a square

7 0

2 years ago

Read 2 more answers