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3 years ago

What does the point lie on if it is equidistant from the two sides of the angle?

Mathematics

1 answer:

Lady_Fox [76]3 years ago

3 0

The point lies on the angle bisector. Any point on the angle bisector is equidistant from the two sides.

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What is the lateral area of the rectangular prism?

weeeeeb [17]

Area of rectangle prism, to find the answer, use this formula: 2 x ( h x d + h x w + d x w )

So it would look like this: 2 x ( 12 x 6 + 12 x 7 + 6 x 7 ) = 396

I would say the answer is B. 396 in2

Hope I helped ; )

4 0

3 years ago

Suppose that poaching reduces the population of an endangered animal by

Sedbober [7]

Answer:

38.26 years.

Step-by-step explanation:

We have been given that the population of an endangered animal by reduces 8% per year. the current population of the animal is 1700. When the population of this animal falls below 70, its extinction is inevitable.

Let us write the model for population of this animal (y) after x years.

Since we know that an exponential decay function is in form: $y=a*(1-r)^x$ , where,

a= Initial value.

r = Rate in decimal form.

Let us convert our given rate in decimal form.

$8\%=\frac{8}{100}=0.08$

Upon substituting a= 1700 and r = 0.08 in exponential function, we will get the model of animal population as:

$y=1700*(1-0.08)^x$

$y=1700*(0.92)^x$

Let us find, when the animal population will face extinction by substituting y=70 in our function.

$70=1700*(0.92)^x$

$\frac{70}{1700}=\frac{1700*(0.92)^x}{1700}$

$0.0411764705882353=0.92^x$

Let us take natural log of both sides of our equation.

$ln(0.0411764705882353)=ln(0.92^x)$

$ln(0.0411764705882353)=x*ln(0.92)$

$-3.1898882879949483163=x*-0.0833816089390511$

$x=\frac{-3.1898882879949483163}{-0.0833816089390511}$

$x=38.2564971890460849445284\approx 38.26$

Therefore, the population of the animal will face extinction after 38.26 years.

5 0

4 years ago

The function f(x) = 200(0.5)x/50 models the amount in pounds of a particular

victus00 [196]

<u>Answer:</u>

29 years

<u>Step-by-step explanation:</u>

Given the function $f(x)= 200(0.5)^{\frac{x}{50} }$ , where x stands for the number of years since the material was put into the vault, we can plug 140 into x to find the amount leftover.
Another way of doing this is to change the function to $f(x)=200(0.5^{\frac{1}{50} })^{x}$ which are equivalent functions, and then plug 140 into x. This function is helpful if you also needed to find the rate.
I'll use the 1st function because the question doesn't ask for the rate