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Sergeu [11.5K]
4 years ago
11

A=4_0e^-0.05(14) How do I solve this?

Mathematics
1 answer:
deff fn [24]4 years ago
6 0
Multiply it then u add
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A bungee jumper is jumping off the New River Gorge Bridge in West Virginia, which has a height of 876 feet. The cord stretches 8
Alex Ar [27]

I say B. That is what I think at least.

7 0
3 years ago
A company has a cost equation of c=0.925x^2-4x+20 and a profit equation of p=-1.125x^2+6x+40. Solve for the breakeven point.
lana66690 [7]
0.925x^2 - 4x + 20 = -1.125x^2 + 6x + 40 (at break even point)

2.05x^2 - 10x - 20 = 0

x =  [ - (-10) +/- sqrt(100 - 4*2.05*-20) / (2*2.05) 

x =  6.40, -1.52   Ignore the negative 

Answer is  6.40


3 0
3 years ago
Which equation is the inverse of y = 2x^2 - 8?
evablogger [386]

Answer: A

Step-by-step explanation:

y=2x^2-8

1. Swap x and y.

x=2y^2-8

2. Solve for the new y.

Add 8

x+8=2y^2

Divide by 2.

\frac{x+8}{2}=y^2

Extract the square root.

\sqrt{\frac{x+8}{2} }=y

6 0
4 years ago
The distance from Wakefield to London is 180 miles. A train travels this distance in 2 hours 15 minutes. Calculate the average s
Readme [11.4K]

Answer:

v = 80 mph

Step-by-step explanation:

Given that,

The distance from Wakefield to London is 180 miles.

The train travels this distance in 2 hours 15 minutes.

We need to find the average speed of the train. The average speed of the train is equal to the total distance covered divided by the time taken.

v=\dfrac{d}{t}\\\\v=\dfrac{180\ miles}{(2+\dfrac{15}{60})\ h}\\\\v=80\ mph

So, the required average speed of the train is 80 mph.

4 0
3 years ago
Indicate whether the function represents an exponential growth or decay.
svetoff [14.1K]

Answer:

1) decay

2) growth

3) growth

Step-by-step explanation:

A generic exponential function can be written as:

f(x) = A*(r)^x

Where:

A is the initial amount of something.

r is the rate of growth.

x is the variable, usually, represents time.

if r > 1, we have an exponential growth.

if r < 1, we have an exponential decay.

1) f(x) = (3/4)^x

in this case we have:

A = 1

r = (3/4) = 0.75

Clearly, r < 1.

Then this is an exponential decay.

2) f(x) = (1/6)*4^x

In this case we have:

A = (1/6)

r = 4

Here we have r > 1.

Then this is an exponential growth.

3) f(x) = (1/4)*(5/2)^x

in this case we have:

A = 1/4

r = 5/2 = 2.5

here we have r > 1, then this is an exponential growth.

8 0
3 years ago
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