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Crazy boy [7]
4 years ago
7

A team has won 60 percent of the 20 games it has playes so far this season. If the team plays a total of 50 games all season and

wins 80 percent of the remaining games, then the percent of games it won for the entire season will be
1. 66%
2. 69%
3. 70%
4. 72%
5. 74% ...?
Mathematics
2 answers:
vladimir2022 [97]4 years ago
5 0

Answer:  Option '4' is correct.

Step-by-step explanation:

Since we have given that

Total number of games =50

Firstly, he played 20 games.

Percentage of games they won = 60%

Number of games they won is given by

\dfrac{60}{100}\times 20\\\\=0.6\times 20\\\\=12

Remaining number of games = 50-20=30

Percentage of remaining games they won = 80%

So, number of games they won is given by

\dfrac{80}{100}\times 30\\\\=0.8\times 30\\\\=24

So, total number of games they won is given by

12+24 = 36

So, Percentage of games they won for the entire season will be

\dfrac{36}{50}\times 100\\\\=36\times 2\\\\=72\%

Hence, Option '4' is correct.

Luden [163]4 years ago
3 0
So far team has won =(60/100)*20 = 12 gamesTotal games played in season =5080 percent of the remaining games won = 80 percent of (50-20) = (80/100)*30 = 24 games.Total game won this season = 36So, percent games won in the entire season = (36/50)*100=72%Answer (4)
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(b) With <em>f(x)</em> = <em>x</em> + 3<em>x</em> ² - <em>px</em> + 4 and <em>d(x)</em> = <em>x</em> - 2, we have remainder 8, so

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<em>p</em> = 5

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