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BARSIC [14]
3 years ago
8

Graph the relation. is the relation a function? why or why not? {(0,1), (3,5), (2,2), (-1,4)}

Mathematics
1 answer:
kompoz [17]3 years ago
8 0
It is not a function because when you test it with the vertical line test the line intersect more than once. (If you need the graph, google "graph maker" and plot the points in)
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Please help me with this system of inequalities​!
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Part A: y<4x-8 is a dotted line intercepting the y-axis at -8, and increasing by a value of 4, with shading bellow the line. The Second equation (which I can't fully type out) is a solid line intercepting the y-axis at 5,decreasing by a value of -5/2, and has shading above the line.

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3 years ago
Need help. Have to finish this today!!!!
attashe74 [19]

Answer:

Step-by-step explanation:

1)a ) Let the constant proportionality =k

Direct proportion.So, y = kx

Plugin y = 6 and x =2 and find k

6 = k*2

6/2 = k

k = 3

Constant proportionality = 3

b)  y = 3x

When x = 7  ; y = 3*7 = 21

y = 21

c)When x = 9,

y = 3*9

y = 27

d) When y = 9,

9 = 3*x

9/3 = x

x = 3

e)when y = 30

30 = 3*x

30/3 =x

x = 10

3) y is inversely proportion to x³

y =k\dfrac{1}{x^{3}}\\\\3 =k *\dfrac{1}{2^{3}}\\\\3=k*\dfrac{1}{8}\\\\3*8=k\\\\24 = k

b)  when x = 4

y=24*\dfrac{1}{4*4*4}\\\\y=\dfrac{3}{8}

c) When x = 6

y = 24*\dfrac{1}{6*6*6}\\\\y=\dfrac{1}{9}

d) When y = 24

24= 24*\dfrac{1}{x^{3}}\\\\x^{3}*24=24\\\\x^{3}=\dfrac{24}{24}\\\\x^{3}=1\\\\x = 1

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