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3 years ago

4n + 14 - 5n = -6 what is the value of n

Mathematics

2 answers:

shusha [124]3 years ago

6 0

Answer:

n = 20

Step-by-step explanation:

4n + 14 - 5n = -6

(4n - 5n) + 14 = -6 Combine like terms

-n + 14 = -6

-14 -14 Subtract 14 from both sides

-n = -20

/-1 /-1 Divide by -1

n = 20

Vitek1552 [10]3 years ago

4 0

Answer:

n = 20

Step-by-step explanation:

$4n+14-5n=-6$

So we have to simplify the equation.

4n + -5n = -n

So our equation looks like this now -> $-n+14=-6$ .

So now to get -n by itself we get 14 and -6 by itself.

So we do -6 - 14 and we get -20.

So our equation looks like $-n=-20$ .

So now we have to make n positive we do -n ÷ -1 which is n.

And since we divided -n by -1 we have to divide -20 by -1 which is 20.

So n is 20.

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2 years ago

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3 years ago

In a company, 37‰ of the 1500 employees are female. how many are male?

Mashcka [7]

Answer:

945 males

Step-by-step explanation:

1500*37/100= 555 female

1500-555 = 945 male

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7 0

3 years ago

Find the derivative of the function f(x) = (x3 - 2x + 1)(x – 3) using the product rule.

julsineya [31]

Answer:

Step-by-step explanation:

Hello, first, let's use the product rule.

Derivative of uv is u'v + u v', so it gives:

$f(x)=(x^3-2x+1)(x-3)=u(x) \cdot v(x)\\\\f'(x)=u'(x)v(x)+u(x)v'(x)\\\\ \text{ **** } u(x)=x^3-2x+1 \ \ \ so \ \ \ u'(x)=3x^2-2\\\\\text{ **** } v(x)=x-3 \ \ \ so \ \ \ v'(x)=1\\\\f'(x)=(3x^2-2)(x-3)+(x^3-2x+1)(1)\\\\f'(x)=3x^3-9x^2-2x+6 + x^3-2x+1\\\\\boxed{f'(x)=4x^3-9x^2-4x+7}$

Now, we distribute the expression of f(x) and find the derivative afterwards.

$f(x)=(x^3-2x+1)(x-3)\\\\=x^4-2x^2+x-3x^3+6x-4\\\\=x^4-3x^3-2x^2+7x-4 \ \ \ so\\ \\\boxed{f'(x)=4x^3-9x^2-4x+7}$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

6 0

3 years ago

I need help with these two trigonometry problems.

Sloan [31]

Answer:

$B \approx 32.1\°; A \approx 39.0\°$

Step-by-step explanation:

Sine theorem: in any triangle, the ratio between a side and the sine of the opposite angle is constant

$\frac{sin\ \alpha}a = \frac{sin\ \beta}b =\frac{sin\ \gamma}c$

In our case, for the left triangle,

$\frac {sin\ 103\°}{11} =\frac{sin\ B} 6 \rightarrow sin\ B = \frac6{11} sin\ 103\°$

Time to grab a calculator and crunch numbers. Double check your calculator is in degrees and not in radians (plug in sin 30°, if you're getting 0.5 you're good) and you will get

$sin\ B \approx 0.53 \rightarrow B \approx 32.1\°$

Same difference with the right triangle. With the same calculations

$sin\ A = \frac{26}{41} sin 83\° \approx 0.68 \rightarrow A \approx 39.0\°$

5 0

2 years ago