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wolverine [178]
3 years ago
8

The width and length of a rectangle (in feet) are consecutive odd integers. If the length is increased by 5 feet, the area of th

e resulting rectangle is 60 square feet. What is the area of the original rectangle?
25 ft2
30 ft2
35 ft2
Mathematics
2 answers:
vekshin13 years ago
6 0
So here is how you solve the given problem.
Let x be the original width. 
The original length is x + 2.
The new length is (x + 2) + 5 so it is x + 7.
A = L x W
60 = (x + 7) (x)
60 = x2 + 7x
x2 + 7x - 60 = 0
Therefore, x would be equivalent to 5.
Original Area = x (x + 2)
        A = 5 (5 + 2)
       A = 35 ft.
Therefore, the answer would be 35 feet, the third option. Hope this answer helps.

makkiz [27]3 years ago
4 0

I am assuming that you meant 25ft^2, 35ft^2, and 30ft^2, as I had the same question.  Therefore, the answer is 35 ft^2.

You're Welcooooome!:)

Get it? From Moana? Did you watch it, lol? :)

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\huge{ \boxed{ \sf{17.68 \:  {cm}^{2} }}}

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\underline{ \text{Given}} :

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\underline{ \text{To \: find} } :   \sf{Area \: of \: a \: rectangle}

\boxed{ \sf{Area \: of \: a \: rectangle \:  =  \: Length \:  \times  \: Breadth}}

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