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wolverine [178]
3 years ago
8

The width and length of a rectangle (in feet) are consecutive odd integers. If the length is increased by 5 feet, the area of th

e resulting rectangle is 60 square feet. What is the area of the original rectangle?
25 ft2
30 ft2
35 ft2
Mathematics
2 answers:
vekshin13 years ago
6 0
So here is how you solve the given problem.
Let x be the original width. 
The original length is x + 2.
The new length is (x + 2) + 5 so it is x + 7.
A = L x W
60 = (x + 7) (x)
60 = x2 + 7x
x2 + 7x - 60 = 0
Therefore, x would be equivalent to 5.
Original Area = x (x + 2)
        A = 5 (5 + 2)
       A = 35 ft.
Therefore, the answer would be 35 feet, the third option. Hope this answer helps.

makkiz [27]3 years ago
4 0

I am assuming that you meant 25ft^2, 35ft^2, and 30ft^2, as I had the same question.  Therefore, the answer is 35 ft^2.

You're Welcooooome!:)

Get it? From Moana? Did you watch it, lol? :)

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The test scores of a geometry class are given below. 90, 75, 72, 88, 85 The teacher wants to find the variance for the class pop
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72       82              -10                    100
88       82                6                       36
85       82                3                       9

Now that you have a table, you will need the sum of (x-mean)^2 because the sigma sign Σ in statistics, means "the sum of."

64+49+100+36+9 = 258

This will be the answer to your question. The value of the numerator of the calculation will be 258.

 
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