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Pachacha [2.7K]
3 years ago
12

Physics students drop a ball from the top of a 100 foot high building and model its height above the ground as a function of tim

e with the equation   2 ht   . The height, h, is measures in feet and time, t, is 100 16 t measured in seconds. Be careful with all calculations in this problems and remember to do the exponent (squaring) first.
Mathematics
1 answer:
djverab [1.8K]3 years ago
7 0

Complete question :

Physics students drop a ball from the top of a 100 foot high building and model its height as a function time with the equation h(t) = 100 - 16t^2.The height, h, is measured in feet and time, t, is measured is seconds.

Find the value of h(0). Include proper units. What does this output represent?

Answer:

Kindly check explanation

Step-by-step explanation:

The model given :

Height, h as a function of time :

h(t) = 100 - 16t^2

To find h(0): substitute 0 for t in the model defined ;

h(0) = 100 - 16(0)²

h(0) = 100 - 0

h(0) = 100

The output gives the height at which the ball was before it was dropped, it depicts the height when the travel time of the ball is 0

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Lera25 [3.4K]

Answer:

23.4 oz

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Nadia says the hypotenuse of the right triangle has a length of 73 because the Pythagorean theorem states that (28+45)squared eq
Setler79 [48]

Answer: Her solution is incorrect. The hypotenuse is 53 units

Step-by-step explanation: The error occurred when she quoted the Pythagorean theorem. She added up both sides and squared them and made the answer equal to the square of the hypotenuse. She was supposed to have squared them first, before adding up.

The Pythagorean (or Pythagoras) theorem states that the sum of the squares of two sides of a right angled triangle equals the square of the hypotenuse of the triangle. That is, in triangle ABC, if the hypotenuse is given as line AC, the Pythagoras theorem states that

AC^2 = AB^2 + BC^2

Where AC is the hypotenuse and AB and BC are the other two sides.

In Nadia’s solution, if the hypotenuse is given as 73, and the other two sides are 28 and 45, then the Pythagorean theorem properly expressed would be as follows;

73^2 = 28^2 + 45^2

5329 = 784 + 2025

5329 ≠ 2809

As we have determined, writing out the expression as

73^2 = (28 + 45)^2 is very incorrect as this is not the Pythagorean theorem and of course, the triangle cannot have 73 as its hypotenuse as we have determined by properly writing out the Pythagorean theorem.

The correct solution is as follows;

AC^2 = AB^2 + BC^2

AC^2 = 28^2 + 45^2

AC^2 = 784 + 2025

AC^2 = 2809

Add the square root sign to both sides of the equation

AC = 53

Therefore, the hypotenuse is 53 units

4 0
3 years ago
Read 2 more answers
10) g(n) = -21+ 3n; Find gl-6)<br> A) 152 <br> B) -20<br> C) 1<br> D) 90
defon
10) g(n) = -21+ 3n; Find gl-6)
A) 152
B) -20
C) 1
D) 90
Your answer would be B

If this helped can I please get brainliest
6 0
3 years ago
[!]Urgent[!] What is another way to summarize the outcome of this proof?​
Marina CMI [18]

Answer:

B. Vertical angles are congruent

Step-by-step explanation:

The instructions are to prove that ∠ANR and ∠VNE are congruent, and ∠ANR and ∠VNE are vertical angles.

I hope this helps :)

8 0
3 years ago
Find the interquartile range for the box plot below.*
alexgriva [62]

Answer:

Step 1: Put the numbers in order. ...

Step 2: Find the median. ...

Step 3: Place parentheses around the numbers above and below the median. Not necessary statistically, but it makes Q1 and Q3 easier to spot. ...

Step 4: Find Q1 and Q3. ...

Step 5: Subtract Q1 from Q3 to find the interquartile range.

Step-by-step explanation:

u should do those step and i think u will find the answer

6 0
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