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goldfiish [28.3K]
2 years ago
11

Open the picture and answer it pls

Mathematics
2 answers:
juin [17]2 years ago
8 0

Answer:

3.5 centimeters.

Step-by-step explanation:

If the perimeter is equal to 11.5 centimeters, and we have the lengths of 2 sides, we can add them together and subtract that sum from the perimeter to get the value of the missing side length.

2.5 + 5.5 = 8

11.5 - 8 = 3.5

Therefore, the side length is equal to 3.5.

Nastasia [14]2 years ago
3 0

Answer:

3.5

Step-by-step explanation:

11.5 - 2.5 = 9

9 - 5.5 = 3.5

and scalene triange means none of the 3 sides are equal...

3.5 does not equal 5.5 or 2.5

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The slope intercept form is  y=mx+b
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6 0
3 years ago
Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL
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Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

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             => JK = \sqrt{(1-2)^{2} + (1-5)^{2}  } = \sqrt{(-1)^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • J(2;5); L(5;2)

             => JL = \sqrt{(5-2)^{2} + (2-5)^{2}  } = \sqrt{3^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • K(1;1); L(5;2)

             =>  KL = \sqrt{(5-1)^{2} + (2-1)^{2}  } = \sqrt{4^{2}+1^{2}  } = \sqrt{1+16}=\sqrt{17}

In the triangle QNP, the sides can be calculate as following:

  • Q(-4;4); N(-3;0)

             => QN = \sqrt{[-3-(-4)]^{2} + (0-4)^{2}  } = \sqrt{1^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • Q (-4;4); P(-7;1)

   => QP = \sqrt{[-7-(-4)]^{2} + (1-4)^{2}  } = \sqrt{(-3)^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • N(-3;0); P(-7;1)

             =>  NP = \sqrt{[-7-(-3)]^{2} + (1-0)^{2}  } = \sqrt{(-4)^{2}+1^{2}  } = \sqrt{16+1}=\sqrt{17}

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

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