<u>Answer:</u> The EMF of the cell is coming when the cell having diluted concentration is getting oxidized.
<u>Explanation:</u>
We are given a cell which contains two
half cells. This means that the standard electrode potential of the cell will be 0.
For a reaction to be spontaneous, the EMF of the cell must be positive. If the EMF of the cell is negative, the reaction will be non-spontaneous and will not take place.
For a reaction to be spontaneous, the diluted cell must get oxidized.
The half reaction for the given cell follows:
<u>Oxidation half reaction:</u> 
<u>Reduction half reaction:</u> 
Net reaction: 
To calculate the EMF of the cell, we use Nernst equation:
![E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Zn^{2+}_\text{{(diluted)}}]}{[Zn^{2+}_{\text{(concentrated)}}]}](https://tex.z-dn.net/?f=E_%7Bcell%7D%3DE%5Eo_%7Bcell%7D-%5Cfrac%7B0.0592%7D%7Bn%7D%5Clog%20%5Cfrac%7B%5BZn%5E%7B2%2B%7D_%5Ctext%7B%7B%28diluted%29%7D%7D%5D%7D%7B%5BZn%5E%7B2%2B%7D_%7B%5Ctext%7B%28concentrated%29%7D%7D%5D%7D)
where,
n = number of electrons in oxidation-reduction reaction = 2
= ?
= 
= 2.0 M
Putting values in above equation, we get:


Hence, the EMF of the cell is coming when the cell having diluted concentration is getting oxidized.
Answer:
sun
Explanation:
source means where it comes from and the source of energy comes from the sun
Answer:
23.76g
Explanation:
To solve for the mass of carbon dioxide (CO2), let us first obtain the number of mole of CO2.
From the question, the following were obtained:
V = 8.13L
P = 204kPa = 204000Pa
Recall: 101325Pa = 1atm
204000Pa = 204000/101325 = 2atm
T = 95°C = 95 + 273 = 368K
R = 0.082atm.L/K/mol
n =?
PV = nRT
n = PV /RT
n = 2 x 8.13/ 0.082 x 368
n = 0.54mole
Now let us convert 0.54mole of CO2 to gram. This is illustrated below:
Molar Mass of CO2 = 12 + (16x2) = 12 + 32 = 44g/mol
Number of mole of CO2 = 0.54mole
Mass of CO2 =?
Number of mole = Mass /Molar Mass
Mass = number of mole x molar Mass
Mass of CO2 = 0.54 x 44
Mass of CO2 = 23.76g
Answer:
The electrons farthest from the nucleus of the atom.
hope this helps!
1-pentyne boiling point is 40 degrees C it is lower than the one for 1-octyne which is 126 degrees C the vapor pressure for 1-butene is higher at low temperatures than 1-heptene.These are due to the difference in the length of the chains. The strong molecular forces are stronger in large molecules. There is more energy needed to move large molecules to the vapor phase when in liquid form.