The answer is (C) as the definitions states that atomic mass is the number of protons and neutrons.
Hope this helps :).
The mass of 2,301 grams of sodium in ounces is 0.0811757609 ounces.
The amount of sodium recommended by American heart association is 2301 mg. This limit should not be crossed in a day.
We have to convert Mass of sodium from mg to ounces.
We know,
1 ounce = 28.3459 grams.
We also know,
1 gram = 1000 milligrams.
So,
28.3459 grams = 28.3459 x 1000 milligrams.
28.3459 grams = 28345.9 milligrams.
1 ounce = 28345.9 mg.
1 mg = 1/28345.9 ounces
Weight of sodium 2301mg in ounces,
2301mg = 2301/28345.9 ounces
Dividing till last significant figure,
2301 mg = 0.0811757609 ounces.
Mass of sodium in ounces is 0.0811757609.
To know more about Unit conversion, visit,
brainly.com/question/97386
#SPJ9
Answer:
5.06atm
Explanation:
Using the combined gas law equation;
P1V1/T1 = P2V2/T2
Where;
P1 = initial pressure (atm)
P2 = final pressure (atm)
V1 = initial volume (Litres)
V2 = final volume (Litres)
T1 = initial temperature (K)
T2 = final temperature (K)
According to the information provided in this question;
P1 = 1.34 atm
P2 = ?
V1 = 5.48 L
V2 = 1.32 L
T1 = 61 °C = 61 + 273 = 334K
T2 = 31 °C = 31 + 273 = 304K
Using P1V1/T1 = P2V2/T2
1.34 × 5.48/334 = P2 × 1.32/304
7.34/334 = 1.32P2/304
Cross multiply
334 × 1.32P2 = 304 × 7.34
440.88P2 = 2231.36
P2 = 2231.36/440.88
P2 = 5.06
The final pressure is 5.06atm
Answer is: Ksp for calcium sulfate is 2.36·10⁻⁴.
Balanced chemical reaction (dissociation):
CaSO₄(s) → Ba²⁺(aq) + SO₄²⁻(aq).
m(CaSO₄) = 0.209 g.
n(CaSO₄) = m(CaSO₄) ÷ M(CaSO₄).
n(CaSO₄) = 0.209 g ÷ 136.14 g/mol.
n(CaSO₄) = 0.00153 mol.
s(CaSO₄) = n(CaSO₄) ÷ V(CaSO₄).
s(CaSO₄) = 0.00153 mol ÷ 0.1 L = 0.0153 M.
Ksp = [Ca²⁺] · [SO₄²⁻].
[Ca²⁺] = [SO₄²⁻] = s(CaSO₄).
Ksp = (0.0153 M)² = 2.36·10⁻⁴.
Answer:
With billions of moving particles colliding into each other, an area of high energy will slowly transfer across the material until thermal equilibrium is reached (the temperature is the same across the material).
