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satela [25.4K]
3 years ago
6

All this questions help

Mathematics
1 answer:
Brrunno [24]3 years ago
5 0
The answer is..
Yo Face Bruh!!!
You might be interested in
What is the range the 3rd side of the triangle can be be with 15 cm 14 cm ?
Volgvan

Answer:

20.5 cm

Step-by-step explanation:

I just used Pythagorean theorem  in which c^2=a^2+b^2

so this is c^2= 225 + 196 and then you get c^2= 421 and finally you get the square root of 421 so this way you finally get 20.5 cm

6 0
3 years ago
1. The graph below represents five cities and the routes between them. An out-of-state road inspector is asked to fly into Potts
ollegr [7]

Please see attached image for the graph.


a.       Yes, it is mathematically possible because the degree of vertices for P=3, T=3, M=2, C=4, and R=2 and in Euler’s theorem, the graph has to be connected, which in this case it is and the number of vertices in the graph whose vertices is odd, is 0 or 2. And in this case, we have 2 that have a degree of vertices that are odd, therefore mathematically this is possible for the driver. The route would be P > R > C > M > T > C > P > T.

 

b.       <span>It is mathematically possible. The router would be P > C > R > T > M > C > T. Essentially, you travel each road once.

</span>

c.       The driver would use a Hamiltonian circuit. The route would be J > R > A > C > V > M > T > P > J.

8 0
4 years ago
A rectangle has an area of 30 square units and a perimeter of 34 meters.what are the dimensions of this rectangle
enyata [817]
P=2L+2W
A=WL

Therefore, if P=34, and A=30, then let us find the factors of 30 that could give a sum of half of the perimeter which is 34. Therefore:

P=2*15+2*2
A=15*2

P=34
A=30

Therefore, the dimensions of this rectangle are 15 and 2.
7 0
3 years ago
Help me please. Your the best if you help.
ASHA 777 [7]

Answer: x = 25, y=15, z = 58

Step-by-step explanation:

4 0
1 year ago
How many different committees can be formed from 10 teachers and 37 students of the committee consist of three teachers and two
pashok25 [27]

Answer:

<em>79,920 different ways</em>

Step-by-step explanation:

Combination has to do with selection:

If we are to select 3 teachers from a pool of 10 teachers to form a committee, this can be done in 10C3 number of ways.

10C3 = 10!/(10-3)!3!

10C3 = 10!/7!3!

10C3 = 10*9*8*7!/7!3!

10C3 = 10*9*8/3*2

10C3 = 720/6

10C3 = 120 ways

Similarly, selecting five 2 students from a pool of 37 students to form a committee, this can be done in 37C2 difference ways;

37C2 = 37!/(37-2)!2!

37C2 = 37!/35!2!

37C2 = 37*36*35!/35!*2

37C2 = 37*36/2

37C2 = 37 * 18

37C2 = 666 ways

<em>Hence the total number of ways that the 5 committees can be selected is expressed as 10C3 * 37C3 = 120 * 666</em>

<em> 120 * 666 = 79,920 ways</em>

3 0
3 years ago
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