Answer:
20.5 cm
Step-by-step explanation:
I just used Pythagorean theorem in which c^2=a^2+b^2
so this is c^2= 225 + 196 and then you get c^2= 421 and finally you get the square root of 421 so this way you finally get 20.5 cm
Please see attached image for the graph.
a.
Yes, it is mathematically possible because the
degree of vertices for P=3, T=3, M=2, C=4, and R=2 and in Euler’s theorem, the
graph has to be connected, which in this case it is and the number of vertices
in the graph whose vertices is odd, is 0 or 2. And in this case, we have 2 that
have a degree of vertices that are odd, therefore mathematically this is
possible for the driver. The route would be P > R > C > M > T > C
> P > T.
b.
<span>It is mathematically possible. The router would be P
> C > R > T > M > C > T. Essentially, you travel each road
once.
</span>
c.
The driver would use a Hamiltonian circuit. The route
would be J > R > A > C > V > M > T > P > J.
Answer: x = 25, y=15, z = 58
Step-by-step explanation:
Answer:
<em>79,920 different ways</em>
Step-by-step explanation:
Combination has to do with selection:
If we are to select 3 teachers from a pool of 10 teachers to form a committee, this can be done in 10C3 number of ways.
10C3 = 10!/(10-3)!3!
10C3 = 10!/7!3!
10C3 = 10*9*8*7!/7!3!
10C3 = 10*9*8/3*2
10C3 = 720/6
10C3 = 120 ways
Similarly, selecting five 2 students from a pool of 37 students to form a committee, this can be done in 37C2 difference ways;
37C2 = 37!/(37-2)!2!
37C2 = 37!/35!2!
37C2 = 37*36*35!/35!*2
37C2 = 37*36/2
37C2 = 37 * 18
37C2 = 666 ways
<em>Hence the total number of ways that the 5 committees can be selected is expressed as 10C3 * 37C3 = 120 * 666</em>
<em> 120 * 666 = 79,920 ways</em>