All categories

2 years ago

3(2x+1)=(10x+2) solve for x

Mathematics

1 answer:

navik [9.2K]2 years ago

4 0

Answer:

x=0.25

Step-by-step explanation:

$3(2x+1)=(10x+2) \\\\6x+3=10x+2\\\\3-2=10x-6x\\\\1=4x\\\\x=1/4=0.25$

You might be interested in

A six-sided number cube labeled 1 through 6 is rolled 500 times. An odd number is rolled 325 times. Compare the experimental pro

Komok [63]

The actual probability of having odd is 3/6=1/2
so no of odds theoretically is 250

but it is 325
so, experimental is higher than theoretical
so answer is B !
and you can go for that !

5 0

3 years ago

Read 2 more answers

Describe a relationship in which one quantity increases as another quantity decreases

Morgarella [4.7K]

Inversely proportional

4 0

3 years ago

Add 12 and 8 and then divide by 8 as an expression help please

Black_prince [1.1K]

Answer:

(12 + 8)/8 = 2.5

7 0

3 years ago

Read 2 more answers

What is the quotient when 4x3 + 2x + 7 is divided by x + 3?

Arte-miy333 [17]

Answer:

The quotient of this division is $(4x^2 -12x + 38)$ . The remainder here would be $-26$ .

Step-by-step explanation:

The numerator $4x^3 + 2x + 7$ is a polynomial about $x$ with degree $3$ .

The divisor $x + 3$ is a polynomial, also about $x$ , but with degree $1$ .

By the division algorithm, the quotient should be of degree $3 - 1 = 2$ , while the remainder shall be of degree $1 - 1 = 0$ (i.e., the remainder would be a constant.) Let the quotient be $a\,x^2 + b\, x + c$ with coefficients $a$ , $b$ , and $c$ .

$4x^3 + 2x + 7 = \left(a\,x^2 + b\, x + c\right)(x + 3)$ .

Start by finding the first coefficient of the quotient.

The degree-three term on the left-hand side is $4 x^3$ . On the right-hand side, that would be $a\, x^3$ . Hence $a = 4$ .

Now, given that $a = 4$ , rewrite the right-hand side:

$\begin{aligned}&\left(4\,x^2 + b\, x + c\right)(x + 3) \cr =& \left(4x^2 + (b\, x + c)\right)(x + 3) \cr =& 4x^2(x + 3) + (bx + c)(x + 3) \cr =& 4x^3 + 12x^2 + (bx + c)(x + 3)\end{aligned}$ .

Hence:

$4x^3 + 2x + 7 = 4x^3 + 12x^2 + (b\,x + c)(x + 3)$

Subtract $\left(4x^3 + 12x^2\right$ from both sides of the equation:

$-12x^2 + 2x + 7 = (b\,x + c)(x + 3)$ .

The term with a degree of two on the left-hand side has coefficient $(-12)$ . Since the only term on the right hand side with degree two would have coefficient $b$ , $b = -12$ .

Again, rewrite the right-hand side:

$\begin{aligned}&\left(-12 x + c\right)(x + 3) \cr =& \left(-12 x+ c\right)(x + 3) \cr =& (-12x)(x + 3) + c(x + 3) \cr =& -12x^2 -36x + (bx + c)(x + 3)\end{aligned}$ .