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AlexFokin [52]
3 years ago
11

The area of a trapezoid is 69.6 in2 and its altitude is 8.7 in. Find the perimeter of the trapezoid if the sum of its legs is eq

ual to the sum of its bases.
Mathematics
2 answers:
BaLLatris [955]3 years ago
7 0
1. To solve this problem, you must apply the formula for calculate the area of the trapezoid, which is:
 
 A=(B+b)h/2
 
 A is the area of the trapezoid (A=69.6 in²).
 (B+b) is the sum of the bases of the trapezoid.
 h is the height of the trapezoid (h=8.7 in).
 
 2. When you clear the sum of the bases (B+b), you have:
 
 A=(B+b)h/2
 2A=<span>(B+b)h
</span><span> (B+b)=2A/h
</span> (B+b)=2(69.6 in²)/(8.7 in)
 (B+b)=16 in
 
 3. The problem says that <span>the sum of its legs is equal to the sum of its bases, therefore, the perimeter is:
</span> 
 Sum of the legs=Sum of the bases (B+b)=16 in
 
 Perimeter=16 in+16 in
 Perimeter=32 in
FinnZ [79.3K]3 years ago
7 0

Answer:

32

Step-by-step explanation:

figure it out

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dem82 [27]

By applying Pythagoras theorem, the missing segment lengths of this triangles include:

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<h3>How to find the missing segment lengths?</h3>

Since triangle ACD is a right-angle triangle, we would use Pythagoras theorem to find the missing segment lengths of this triangles as follows:

c² = a² + b² ≡ AD² = CD² + AC²

Next, we would use cos trigonometric ratio to find side CD,

cos45 = adjacent/hypotenuse

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1/√2 = CD/20

CD = 1/√2 × 20

CD = (20√2)/2

CD = 10√2

For side AC, we have:

AD² = CD² + AC²

AC² = AD² - CD²

AC² = 20² - (10√2)²

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AC = √200

AC = 10√2

From triangle ABC, we have:

cos45 = BC/10√2

BC = 10√2 × cos45

BC = 10√2 × 1/√2

BC = (10√2)/√2

BC = 10

For side AB, we have:

AB² = (10√2)² - 10²

AB² = 200 - 100

AB² = 100

AB = 10.

Read more on Pythagorean theorem here: brainly.com/question/23200848

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