Ask question

Ask question

All categories

dimulka [17.4K]

3 years ago

15

You decide to get an estimate on the cost of repairs for the green food truck. The mechanic explains that the cost of the repair

s comes out to be about $9,500. This price includes the cost of labor and the cost of the parts needed to do the repairs. If labor costs are 3/5 the cost of the parts, how much would you save by doing the repairs yourself and just purchasing the parts?

1 answer:

I am Lyosha [343]3 years ago

7 0

Answer:

you save labor : 3562.50

Step-by-step explanation:

You want to calculate for labor.

labor = 3/5 (parts)

labor + parts = $9500 (total costs)

3/5 parts + parts =9500

3/5 parts + 5/5 parts = 9500

8/5 parts=9500

5/8(8/5 parts) = 5/8 (9500)

‘parts = 5937.50

labor=3562.50 (3/5 x 5937.50)

total = 9500

You might be interested in

All rectangles are paralloelograms

Anni [7]

Answer:

not all rectangles are paralloelograms.

Step-by-step explanation:

8 0

3 years ago

I neee help with my division imma stuck

rosijanka [135]

Answer: what division?

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

In the figure below, EH GJ and FI intersects EH at G as shown below.

Pachacha [2.7K]

Answer:

D. 15°

Step-by-step explanation:

EGF and HGF are equal and 75°

since JGH is 90° we can say JGI is 90 - 75 = 15°

5 0

3 years ago

A 7-mile bike race is divided into 4 equal sections. Which equation shows how to find the number of miles in each section?

guapka [62]

You would divide 7 by 4. (7/4) each section would be 1.75 miles :)

4 0

3 years ago

Read 2 more answers

The angle of elevation from me to the top of a hill is 51 degrees. The angle of elevation from me to the top of a tree is 57 deg

julia-pushkina [17]

Answer:

Approximately $101\; \rm ft$ (assuming that the height of the base of the hill is the same as that of the observer.)

Step-by-step explanation:

Refer to the diagram attached.

Let $\rm O$ denote the observer.
Let $\rm A$ denote the top of the tree.
Let $\rm R$ denote the base of the tree.
Let $\rm B$ denote the point where line $\rm AR$ (a vertical line) and the horizontal line going through $\rm O$ meets. $\angle \rm B\hat{A}R = 90^\circ$ .

Angles:

Angle of elevation of the base of the tree as it appears to the observer: $\angle \rm B\hat{O}R = 51^\circ$ .
Angle of elevation of the top of the tree as it appears to the observer: $\angle \rm B\hat{O}A = 57^\circ$ .

Let the length of segment $\rm BR$ (vertical distance between the base of the tree and the base of the hill) be $x\; \rm ft$ .

The question is asking for the length of segment $\rm AB$ . Notice that the length of this segment is $\mathrm{AB} = (x + 20)\; \rm ft$ .

The length of segment $\rm OB$ could be represented in two ways:

In right triangle $\rm \triangle OBR$ as the side adjacent to $\angle \rm B\hat{O}R = 51^\circ$ .
In right triangle $\rm \triangle OBA$ as the side adjacent to $\angle \rm B\hat{O}A = 57^\circ$ .

For example, in right triangle $\rm \triangle OBR$ , the length of the side opposite to $\angle \rm B\hat{O}R = 51^\circ$ is segment $\rm BR$ . The length of that segment is $x\; \rm ft$ .

$\begin{aligned}\tan{\left(\angle\mathrm{B\hat{O}R}\right)} = \frac{\,\rm {BR}\,}{\,\rm {OB}\,} \; \genfrac{}{}{0em}{}{\leftarrow \text{opposite}}{\leftarrow \text{adjacent}}\end{aligned}$ .

Rearrange to find an expression for the length of $\rm OB$ (in $\rm ft$ ) in terms of $x$ :

$\begin{aligned}\mathrm{OB} &= \frac{\mathrm{BR}}{\tan{\left(\angle\mathrm{B\hat{O}R}\right)}} \\ &= \frac{x}{\tan\left(51^\circ\right)}\approx 0.810\, x\end{aligned}$ .

Similarly, in right triangle $\rm \triangle OBA$ :

$\begin{aligned}\mathrm{OB} &= \frac{\mathrm{AB}}{\tan{\left(\angle\mathrm{B\hat{O}A}\right)}} \\ &= \frac{x + 20}{\tan\left(57^\circ\right)}\approx 0.649\, (x + 20)\end{aligned}$ .

Equate the right-hand side of these two equations:

$0.810\, x \approx 0.649\, (x + 20)$ .

Solve for $x$ :

$x \approx 81\; \rm ft$ .

Hence, the height of the top of this tree relative to the base of the hill would be $(x + 20)\; {\rm ft}\approx 101\; \rm ft$ .

6 0

3 years ago