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aleksklad [387]
3 years ago
8

Help in maths question!

Mathematics
2 answers:
aksik [14]3 years ago
7 0

(i) Suppose ∠ADB =∠ x. Since a triangle's angles sum up to 180°, we know that x+α+β=180°. We also know that x+∠ADC=180, so therefore α+β=∠ADC

(ii) The same logic that a triangle's interior angles equal 180°, we know that α+α+β+∠DAC=180. Therefore, 180-α-α-β=∠DAC.

(iii) We know that ∠DAE = 180-2α+β, which means 180-∠DAE = 2α+β, which means (2α+β)/2 which finally means α+β/2, which we will call p. We will call ∠EDC k. Now we know that p+k=α+β, which means k=α+β-p, then α+β-p, but p = (α+β/2), so we plug that in. Finally, everything can be simplified into 3/2*p.

mrs_skeptik [129]3 years ago
7 0

(i) Suppose ∠ADB =∠ x. Since a triangle's angles sum up to 180°, we know that x+α+β=180°. We also know that x+∠ADC=180, so therefore α+β=∠ADC

(ii) The same logic that a triangle's interior angles equal 180°, we know that α+α+β+∠DAC=180. Therefore, 180-α-α-β=∠DAC.

(iii) We know that ∠DAE = 180-2α+β, which means 180-∠DAE = 2α+β, which means (2α+β)/2 which finally means α+β/2, which we will call p. We will call ∠EDC k. Now we know that p+k=α+β, which means k=α+β-p, then α+β-p, but p = (α+β/2), so we plug that in. Finally, everything can be simplified into 3/2*p.

Read more on Brainly.com - brainly.com/question/11502647#readmore

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Hi guys please help meee
Lisa [10]
<h3>Answer: 10</h3>

=======================================================

Explanation:

We'll start off converting each mixed number into an improper fraction.

The formula to use is A \frac{b}{c} = \frac{A*c+b}{c}

So,

A \frac{b}{c} = \frac{A*c+b}{c}\\\\2 \frac{1}{8} = \frac{2*8+1}{8}\\\\2 \frac{1}{8} = \frac{16+1}{8}\\\\2 \frac{1}{8} = \frac{17}{8}\\\\

And,

A \frac{b}{c} = \frac{A*c+b}{c}\\\\2 \frac{2}{3} = \frac{2*3+2}{3}\\\\2 \frac{2}{3} = \frac{6+2}{3}\\\\2 \frac{2}{3} = \frac{8}{3}\\\\

So the task of computing 2 \frac{1}{8} \times 2 \frac{2}{3} is exactly the same as computing \frac{17}{8} \times \frac{8}{3}

Notice how we have an 8 up top and an 8 down below. Those 8's cancel out and we're left with \frac{17}{3}. That fraction does not reduce any further.

The last step is to convert that improper fraction result to a mixed number.

\frac{17}{3} = \frac{15+2}{3}\\\\\frac{17}{3} = \frac{15}{3}+\frac{2}{3}\\\\\frac{17}{3} = 5+\frac{2}{3}\\\\\frac{17}{3} = 5 \frac{2}{3}\\\\

Or you could note that 17/3 leads to 5 remainder 2. The 5 is the whole part and the 2 forms the numerator of the fractional part 2/3.

The value is in A \frac{b}{c} form where

  • A = 5
  • b = 2
  • c = 3

Therefore, A+b+c = 5+2+3 = 10

8 0
2 years ago
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On saturday rhonda filled 3 1/3 buckets with shells . on sunday she filled 4 2/3 buckets with shells .how many more buckets of s
Natasha_Volkova [10]
The answer is 4/3 buckets
6 0
3 years ago
What’s are the steps to solve 52.2x2.3
forsale [732]

Line up the decimal points and multiply the rest like you would normally do it but drop down the decimal at the end
6 0
2 years ago
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Plz help asap.. I have no clue how to do this.
ANTONII [103]

Answer:

Tn=a + (n-1)d

a= first term = 14

n= This is the term you're looking for... In this case... That's the 73rd term

d=Common difference (since its an AP)

d= second term - first term -- Or 3rd term - 2nd term = 23-14

d=9

T = 14 + (73-1)9

T= 14 + (72)9

T= 14 + 648

T=662.

4 0
3 years ago
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You wish to find a 95% confidence interval for the mean number of times men change channels with a remote control during a comme
gogolik [260]
For margin of error to be a maximum of 3:
3 = z*(SD / sqrt(n)), where z is the z-score, SD is the standard deviation and n is the sample size.
z = 1.96 for a 95% confidence interval, and we are given SD = 15.
3 = 1.96*15/sqrt(n)
sqrt(n) = 9.8
n = 96.04 ~ 96 commercials.

4 0
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